我加入了3张桌子:
SELECT TABLE1.FIELD1
FROM TABLE1
JOIN TABLE2 ON TABLE1.ID = TABLE2.FK
JOIN TABLE3 ON TABLE2.ID = TABLE3.FK
我想根据某些条件选择几列TABLE2.FIELD1
,例如TABLE2.FIELD1 WHERE TABLE2.CONDITIONI
,TABLE2.FIELD1 WHERE TABLE3.ANOTHERCONDITION
。
所以最终的结果是这样的:
TABLE1.FIELD1 | TABLE2.FIELD1 BASE ON CON1 | TABLE2.FIELD1 BASED ON CON2
我不确定我是否足够清楚,如果需要,请要求进一步澄清。
示例报告:
Id | Product | Income Quantity | Outcome Quantity
在此示例中,Quantity,在第二个表中仅在产品表上联合的一个字段中。它根据不同的条件在输出中呈现两次,例如,收入在header.flow == 1
之内,而外向在header.flow == -1
之内。
答案 0 :(得分:1)
不确定,但似乎应该使用CASE
声明
select
case when <<cod1>> then
table1.field
when <<cod2>> then
table2.field
end
from your_table1
inner join your_table2 on <<condition>>
答案 1 :(得分:1)
像这样的东西
SELECT ID,
CASE WHEN flow = 1 THEN Quantity ELSE NULL END as 'Income',
CASE WHEN flow = -1 THEN Quantity ELSE NULL END as 'Outcome'
FROM Sample
只需在最后根据需要添加联接,并在CASE声明中更改条件
根据你的评论
我必须使用group by for flow和SUM(quantity)。我会为每种产品分两列。
您可以尝试这样做:
SELECT s1.ID,
(SELECT SUM(Quantity) FROM SAMPLE s2 WHERE s2.ID = S1.ID AND S2.FLOW = 1) as 'Income',
(SELECT SUM(Quantity) FROM SAMPLE s2 WHERE s2.ID = S1.ID AND S2.FLOW = -1) as 'Outgoing'
FROM Sample S1
GROUP BY ID
也可以通过
来实现SELECT DISTINCT s1.ID,
(SELECT SUM(Quantity) FROM SAMPLE s2 WHERE s2.ID = S1.ID AND S2.FLOW = 1) as 'Income',
(SELECT SUM(Quantity) FROM SAMPLE s2 WHERE s2.ID = S1.ID AND S2.FLOW = -1) as 'Outgoing'
FROM Sample S1