Question

所以我有一个函数可以调用ajax并返回一个json字符串。我无法尝试访问我需要的值，下面是我的代码以及我尝试过的一些示例。

    s.search().then(function (specials) {
        var returnJSON = JSON.parse(specials[0]);
        var x = returnJSON.location.x;
        var y = returnJSON.location.y;
        });

当我检查开发工具时，我收到以下错误。

 JSON.parse: unexpected character at line 1 column 2 of the JSON data

这是我对字符串化后的JSON返回值。

[{"feature":{"geometry":{"type":"point","x":-82.9172080701955,"y":42.55426092899978,"spatialReference":{"wkid":102100,"latestWkid":3857}},"symbol":null,"attributes":{"Addr_type":"Postal","Match_addr":"48035, Clinton Township, Michigan","StAddr":"","City":"Clinton Township","score":100},"infoTemplate":null},"extent":{"type":"extent","xmin":-82.922209,"ymin":42.549261,"xmax":-82.912209,"ymax":42.559261,"spatialReference":{"wkid":102100,"latestWkid":3857}},"name":"48035, Clinton Township, Michigan"},{"feature":{"geometry":{"type":"point","x":-84.03589825899667,"y":44.826904141314174,"spatialReference":{"wkid":102100,"latestWkid":3857}},"symbol":null,"attributes":{"Addr_type":"Locality","Match_addr":"Clinton Twp, Michigan","StAddr":"","City":"Clinton Twp","score":100},"infoTemplate":null},"extent":{"type":"extent","xmin":-84.085899,"ymin":44.776904,"xmax":-83.985899,"ymax":44.876904,"spatialReference":{"wkid":102100,"latestWkid":3857}},"name":"Clinton Twp, Michigan"},{"feature":{"geometry":{"type":"point","x":-83.93987906956261,"y":42.065412162742234,"spatialReference":{"wkid":102100,"latestWkid":3857}},"symbol":null,"attributes":{"Addr_type":"Locality","Match_addr":"Clinton Twp, Michigan","StAddr":"","City":"Clinton Twp","score":100},"infoTemplate":null},"extent":{"type":"extent","xmin":-83.98988,"ymin":42.015412,"xmax":-83.88988,"ymax":42.115412,"spatialReference":{"wkid":102100,"latestWkid":3857}},"name":"Clinton Twp, Michigan"},{"feature":{"geometry":{"type":"point","x":-82.93354923650725,"y":42.60054198222781,"spatialReference":{"wkid":102100,"latestWkid":3857}},"symbol":null,"attributes":{"Addr_type":"Locality","Match_addr":"Clinton Twp, Michigan","StAddr":"","City":"Clinton Twp","score":100},"infoTemplate":null},"extent":{"type":"extent","xmin":-82.98355,"ymin":42.550542,"xmax":-82.88355,"ymax":42.650542,"spatialReference":{"wkid":102100,"latestWkid":3857}},"name":"Clinton Twp, Michigan"},{"feature":{"geometry":{"type":"point","x":-83.97095926895429,"y":42.07240087260328,"spatialReference":{"wkid":102100,"latestWkid":3857}},"symbol":null,"attributes":{"Addr_type":"Locality","Match_addr":"Clinton, Michigan","StAddr":"","City":"Clinton","score":94.29},"infoTemplate":null},"extent":{"type":"extent","xmin":-84.02096,"ymin":42.022401,"xmax":-83.92096,"ymax":42.122401,"spatialReference":{"wkid":102100,"latestWkid":3857}},"name":"Clinton, Michigan"},{"feature":{"geometry":{"type":"point","x":-84.6015125489642,"y":42.943655651388326,"spatialReference":{"wkid":102100,"latestWkid":3857}},"symbol":null,"attributes":{"Addr_type":"SubAdmin","Match_addr":"Clinton, Michigan","StAddr":"","City":"Clinton","score":94.29},"infoTemplate":null},"extent":{"type":"extent","xmin":-84.839514,"ymin":42.705656,"xmax":-84.363514,"ymax":43.181656,"spatialReference":{"wkid":102100,"latestWkid":3857}},"name":"Clinton, Michigan"}]

我正在尝试访问候选位置x值和y值。

Answer 1

您的JSON中有一些字符串在不同的行上。当您将JSON复制并粘贴到linter中时（例如：json linter），您将看到错误。

修改：您编辑了问题，因此您现在使用的是有效的JSON。

当您已经拥有有效的JSON时，无需解析您的JSON。您只需选择正确的密钥即可。查看您的JSON，您可以选择 x 和 y ，如下所示：

var returnJSON = specials[0]; var x = returnJSON.feature.geometry.x; var y = returnJSON.feature.geometry.y;

查看此codepen以获取示例。

Answer 2

您通常不需要“解析”从服务返回的JSON。它已经是then回调中的Javascript对象。

s.search().then(function (specials) {
    var firstItem = specials[0];
    var x = firstItem.location.x;
    var y = firstItem.location.y;
});

但是，应该注意的是，specials数组中返回的第一个项目没有符合您发布的JSON示例的属性location。

也许你在firstItem.feature.geometry.x之后，但我不确定。

从JSON返回的数据中获取值

2 个答案: