如何将数字中的随机电话号码转换为字典中的单词以及如何从文本中选择它并将其转换为python?

时间:2015-08-12 17:47:40

标签: python dictionary replace type-conversion phone-number

我正在尝试使用以下代码使用词典将随机电话号码从一个数字转换为单词:

dict_1 = {07: 'zero seven'}

dict_2 = {2: 'two', 3: 'three', 4: 'four', 5: 'five', 6: 'six', 7: 'seven', 8: 'eight'}

dict_3 = {0: 'zero', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five', 6: 'six', 7: 'seven', 8: 'eight', 9: 'nine'}

def main():

    import re
    no_tel = raw_input("Enter a phrase: ")
    mat = re.search('(\d{10})', no_tel)
    a_no = mat.group(0)
    first_part = a_no[0:2]
    second_part = a_no[2:3]
    third_part = a_no[3:]

    it_works = False
    if dict_1.get(int(first_part)) != None:
        a_print = dict_1.get(int(first_part))
        it_works = True
    else:
        print "Error!"

    if dict_2.get(int(second_part)) != None:
        b_print = dict_2.get(int(second_part))
        it_works = True
    else:
        print "Error!"
    fourth_part = third_part[0]
    fifth_part = third_part[1]
    sixth_part = third_part[2]
    seventh_part = third_part[3]
    eighth_part = third_part[4]
    ninth_part = third_part[5]
    tenth_part = third_part[6]

    if dict_3.get(int(fourth_part)) != None:
        d_print = dict_3.get(int(fourth_part))
        it_works = True

    if dict_3.get(int(fifth_part)) != None:
        e_print = dict_3.get(int(fifth_part))
        it_works = True

    if dict_3.get(int(sixth_part)) != None:
        f_print = dict_3.get(int(sixth_part))
        it_works = True

    if dict_3.get(int(seventh_part)) != None:
        g_print = dict_3.get(int(seventh_part))
        it_works = True

    if dict_3.get(int(eighth_part)) != None:
        h_print = dict_3.get(int(eighth_part))
        it_works = True

    if dict_3.get(int(ninth_part)) != None:
        i_print = dict_3.get(int(ninth_part))
        it_works = True


    if dict_3.get(int(tenth_part)) != None:
        j_print = dict_3.get(int(tenth_part))
        it_works = True

    if it_works == True:
        telephone = " ". join([a_print, b_print, d_print, e_print, f_print, g_print, h_print, i_print, j_print])
        correct_no = re.sub ('(first_part)(second_part)(third_part)', telephone, no_tel)
        print correct_no
    else:
        print "Error!"


if __name__ == '__main__':
    main()

运行此程序后,输出应为:

Enter a phrase: My phone no is 0734123456

以上代码应转换为 - >

My phone no is zero seven two three one two three four five six

或此格式的任何其他电话。

此外,如何将代码应用于包含电话号码的文档? 我不知道怎么做,从文本中读取然后显示替换的电话号码的内容,我不知道。

1 个答案:

答案 0 :(得分:4)

为什么不呢:

def phone(number):
    numbers = ['zero', 'one', 'two', 'three', 'four',
               'five', 'six', 'seven', 'eight', 'nine']
    return ' '.join(numbers[c] for c in map(int, number))

结果:

>>> phone('0734123456')
'zero seven three four one two three four five six'