Question

所以我逐行阅读元素列表。他们像这样登录到控制台：

one
two
three

我想要的是我的数组硬编码与文本进行逐行比较所以期望看起来像：

one = one
two = two
three = three

roomsAsc = ['one', 'two', 'three'];

for (var i = 0; i < count; i++) {

  //scrolls down the list element by element
  browser.executeScript("arguments[0].scrollIntoView();", MyLists.get(i).getWebElement());
  myLists.get(i).getText().then(function(text) {
    //trying to get my array line be line like as java would
    expect(text).toEqual(roomsAsc[i]);
    //this says undefined in output
    console.log(roomsAsc + 'array');
    console.log(text);
  });
}
//expect(myLists).toEqual(roomsAsc);
});

上面的代码滚动，直到所有元素的列表都可见。列表中有28个。我把它们全部打印到控制台，但是，只有非可视元素被存储，前13个在数组中是空白的，这是奇数，所以现在我试图逐行预期。

Answer 1

我在.then（）函数中使用for循环中的迭代器时遇到了麻烦。所以我已经声明了另一个变量来迭代另一个数组并在.then（）函数中进行递增。看看这是否能给你带来更好的结果

roomsAsc = ['one', 'two', 'three'];
var j = 0;  // using this since the i iterator in the for loop doesn't work within a then function
for (var i = 0; i < count; i++) {

  //scrolls down the list element by element
  browser.executeScript("arguments[0].scrollIntoView();", MyLists.get(i).getWebElement());
  myLists.get(i).getText().then(function(text) {
    //trying to get my array line be line like as java would
    expect(text).toEqual(roomsAsc[j++]);
    //this says undefined in output
    console.log(roomsAsc + 'array');
    console.log(text);
  });
}
//expect(myLists).toEqual(roomsAsc);
});

Answer 2

您是否尝试使用map？

myLists.map(function(row, index){
  return {
    text: row.getText(),
    name: roomsAsc[index]
  }
}).then(function(theValues){
  // You will get an array:
  // [{name: 'one', text: 'one text'}, ...]
});

Answer 3

您可能遇到与闭包有关的问题。从以下链接中了解有关闭包的更多信息 - Using protractor with loops

更好的解决方案是使用递归 -

 function loop(i){
     if(i>count)
              {
                return null;
              }
              else
              {
                //scrolls down the list element by element
                browser.executeScript("arguments[0].scrollIntoView();",MyLists.get(i).getWebElement());
  myLists.get(i).getText().then(function(text) {
    //trying to get my array line be line like as java would
    expect(text).toEqual(roomsAsc[i]);
    //this says undefined in output
    console.log(roomsAsc + 'array');
    console.log(text);
  })
                return loop(i+1)
              }
            }return loop(0);

Answer 4

我认为您的问题是异步循环。因为您的测试是异步的，所以它会立即触发循环，因此您的测试实际上是从最后一个循环开始的。因此，您的测试首先滚动到最后一个元素，然后仅返回那个可见的。令人困惑，是的。

在那里:)我喜欢的解决方案是使用Immediately Invoked Function Expression（iife），你将索引传递给函数，一切都很好。

像...一样的东西。

roomsAsc = [＆＃39; one＆＃39;，＆＃39; two＆＃39;，＆＃39; three＆＃39;];

for (var i = 0; i < count; i++) {
  (function(i) {
    //scrolls down the list element by element
    browser.executeScript("arguments[0].scrollIntoView();", MyLists.get(i).getWebElement());
    myLists.get(i).getText().then(function(text) {
      //trying to get my array line be line like as java would
      expect(text).toEqual(roomsAsc[i]);
      //this says undefined in output
      console.log(roomsAsc + 'array');
      console.log(text);
    });
  })(i);

}
//expect(myLists).toEqual(roomsAsc);

Expect语句读取数组，然后与我声明的var数组进行比较

4 个答案: