Question

我有以下SQL将我的地址字段连接到ADDRESSLINE1：

SELECT Isnull(ADDRESSLINE1 + Char(13)+Char(10), '')
       + Isnull(ADDRESSLINE2 + Char(13)+Char(10), '')
       + Isnull(ADDRESSLINE3, '') AS ADDRESSLINE1

它返回：

ADDRESSLINE1       
------------------ -----------------------------------
10 TEST ROAD



(1 row(s) affected)

如何修改我的代码，以便ADDRESSLINE2和ADDRESSLINE3为空白＆＃39;＆＃39;然后删除不必要的回车。

我希望：

ADDRESSLINE1       
------------------ -----------------------------------
10 TEST ROAD

(1 row(s) affected)

Answer 1

将CR + LF添加到每一行，然后使用REVERSE(STUFF(REVERSE()))方法删除最后两个字符。

SELECT REVERSE(STUFF(REVERSE(Isnull(ADDRESSLINE1 + Char(13)+Char(10), '')
       + Isnull(ADDRESSLINE2 + Char(13)+Char(10), '')
       + Isnull(ADDRESSLINE3 + Char(13)+Char(10), '')),1,2,'')) AS ADDRESSLINE1

如果您的字段中有空字符串，请尝试此操作：

SELECT REVERSE(STUFF(REVERSE(Isnull(NULLIF(ADDRESSLINE1,'') + Char(13)+Char(10), '')
       + Isnull(NULLIF(ADDRESSLINE2,'') + Char(13)+Char(10), '')
       + Isnull(NULLIF(ADDRESSLINE3,'') + Char(13)+Char(10), '')),1,2,'')) AS ADDRESSLINE1

使用SQL删除回车

1 个答案: