为什么PDO rollback()需要closeCursor()才能反映在输出中?

时间:2015-08-12 11:28:47

标签: php mysql sqlite pdo

在以下代码中,事务失败并调用回滚。

然而,就产出而言:

如果我删除closeCursor(),付款人的余额将打印为-200 $。

如果我指定closeCursor(),付款人的余额将打印为0,这是预期的行为。

这是因为第一个select语句的结果在第二个语句运行之前没有被清除。

为什么我们需要关闭回滚的连接以反映在输出中?在这两种情况下,都会调用回滚,因此在DB中指定值0。所以我希望余额打印为0.

我没有看到关闭连接数据库和获取最新数据库值之间的关系。 Fetch()从DB获取值,所以如果值为0,那么“它认为”它是怎么回事?

这仅适用于SQLite。无论你是否使用closeCursor(),MySQL都会打印0。

<?php
try {
    require_once '../../includes/pdo_connect.php';
    // Set up prepared statements transfer from one account to another
    $amount = 0;
    $payee = 'John White';
    $payer = 'Jane Black';
    $debit = 'UPDATE savings SET balance = balance - :amount WHERE name = :payer';
    ####1st SQL#### $getBalance = 'SELECT balance FROM savings WHERE name = :payer';  
    $credit = 'UPDATE savings SET balance = balance + :amount WHERE name = :payee';

    $pay = $db->prepare($debit);
    $pay->bindParam(':amount', $amount);
    $pay->bindParam(':payer', $payer);

    $check = $db->prepare($getBalance);
    $check->bindParam(':payer', $payer);

    $receive = $db->prepare($credit);
    $receive->bindParam(':amount', $amount);
    $receive->bindParam(':payee', $payee);

    // Transaction
    $db->beginTransaction();
    $pay->execute();
    if (!$pay->rowCount()) {
        $db->rollBack();
        $error = "Transaction failed: could not update $payer's balance.";
    } else {
        // Check the remaining balance in the payer's account
        $check->execute();
        $bal = $check->fetchColumn();
        ########## $check->closeCursor(); 

        // Roll back the transaction if the balance is negative
        if ($bal < 0) {
            $db->rollBack();
            $error = "Transaction failed: insufficient funds in $payer's account.";
        } else {
            $receive->execute();
            if (!$receive->rowCount()) {
                $db->rollBack();
                $error = "Transaction failed: could not update $payee's balance.";
            } else {
                $db->commit();
            }
        }
    }
} catch (Exception $e) {
    $error = $e->getMessage();
}
?>
<!DOCTYPE html>
<html>
<head>
    <meta charset="UTF-8">
    <title>PDO Transaction</title>
    <link href="../../styles/styles.css" rel="stylesheet" type="text/css">
</head>
<body>
<h1>PDO Transactions</h1>
<?php
if (isset($error)) {
    echo "<p>$error</p>";
}
?>
<table>
    <tr>
        <th>Name</th>
        <th>Balance</th>
    </tr>
            ####2nd SQL####<?php foreach ($db->query('SELECT name, balance FROM savings') as $row) { ?>
    <tr>
        <td><?php echo $row['name']; ?></td>
        <td>$<?php echo number_format($row['balance'], 2); ?></td>
    </tr>
    <?php } ?>
</table>
</body>
</html>

1 个答案:

答案 0 :(得分:0)

Ryan Vincent的上述回复是正确的。

所以我指定这个以将我的问题标记为已解决。

谢谢,

的Qwerty