Question

我有一个这样的字符串，我从报告表达式中获取：

 jql = @"(Project in (""CI"") and Status in (""Open"") and issueType in (""Action Item"")) or issueKey = ""GR L-1"" order by Created asc";

我将其转换为JSON并得到如下结果：

 jql = jql.Replace("\"", "'");
 jql = "{" + "\"" + "jql" + "\"" + ": " + "\"" + jql + "\"" + "}";

低于JSON：

   {"jql": "(Project in ('CI') and Status in ('Open') and issueType in ('Action Item')) or issueKey = 'GR L-1' order by Created asc"}

当我像这样做串行化时：

string data = JsonConvert.SerializeObject(request);

它给我这样的刺痛：

 {"jql":"{\"jql\": \"(Project in ('CI') and Status in ('Open') and issueType in ('Action Item')) or issueKey = 'GR L-1' order by Created asc\"}","startAt":0,"maxResults":0,"fields":[]}

这是一种错误的字符串。其实我想要一个像这样的字符串：

{"jql": "(Project in ('CI') and Status in ('Open') and issueType in ('Action Item')) or issueKey = 'GR L-1' order by Created asc"}

注意：我需要这样做：

SearchRequest request = new SearchRequest();
request.JQL = jql;
 string data = JsonConvert.SerializeObject(request);
 string result = runQuery(JiraResource.search, data, "POST");

我试过这样的话：Escape characters after Serializing using Json 但是，这不起作用......

其实我想要一个这样的字符串：

{"jql": "(Project in ('CI') and Status in ('Open') and issueType in ('Action Item')) or issueKey = 'GR L-1' order by Created asc"}

我该怎么做？

Answer 1

此代码适用于您的情况：

string jql = @"(Project in (""CI"") and Status in (""Open"") and issueType in (""Action Item"")) or issueKey = ""GR L-1"" order by Created asc";
jql = jql.Replace("\"", "'");
string result = JsonConvert.SerializeObject(new { jql = jql } );

产生输出

{＆＃34; jql＆＃34;：＆＃34;（项目在（＆＃39; CI＆＃39;）和状态在（＆＃39; Open＆＃39;）和issueType in（＆＃39; ;行动项目＆＃39;））或issueKey =＆＃39; GR L-1＆＃39;按创建的asc＆＃34;}
排序

按预期。

JSON序列化将额外字符添加为＆＃34; \＆＃34;

1 个答案: