Question

我有以下代码作为搜索的对象模型，用户在客户端进行，这非常有效：

public class DemographicAttribute
{
    public string DemographicAttributeValue { get; set; }
}

public class AudienceOperators<T>: IAudienceOperators
{
    public string DemographicAttributeType { get; set; }
    public List<T> Operand { get; set; }
    public string Operator { get; set; }
    //List<U> Entity2 { get; set; }

    public AudienceOperators(List<T> operand, string _operator = null, string demographicAttributeType = "")
    {
        Operand = operand;
        Operator = _operator;
        DemographicAttributeType = demographicAttributeType;
    }
}


public interface IAudienceOperators {}

用法如下：

DemographicAttribute atr1 = new DemographicAttribute();
atr1.DemographicAttributeType = "Occupation";
atr1.DemographicAttributeValue = "White collar";

DemographicAttribute atr2 = new DemographicAttribute();
atr2.DemographicAttributeType = "Occupation";
atr2.DemographicAttributeValue = "Blue";

DemographicAttribute atr3 = new DemographicAttribute();
atr3.DemographicAttributeType = "Age";
atr3.DemographicAttributeValue = "10 - 14";

DemographicAttribute atr4 = new DemographicAttribute();
atr4.DemographicAttributeType = "Age";
atr4.DemographicAttributeValue = "15 - 25";

AudienceOperators<String> op1 = new AudienceOperators<String>(new List<String> { atr1.DemographicAttributeValue, atr2.DemographicAttributeValue }, "OR", atr1.DemographicAttributeType);
AudienceOperators<String> op2 = new AudienceOperators<String>(new List<String> { atr3.DemographicAttributeValue, atr4.DemographicAttributeValue }, "OR", atr3.DemographicAttributeType);
AudienceOperators<IAudienceOperators> op3 = new AudienceOperators<IAudienceOperators>(new List<IAudienceOperators> { op1, op2 }, "AND");

为了能够创建通用类的实例，我需要创建空白接口。但我认为，这不是最好的代码实践。还有其他办法吗？

Answer 1

你不需要做任何特别的事情来允许＆＃34;递归＆＃34;通用实例。

public class Recursively<T> {
    public T Instance { get; set; }
}

...

var recursively = new Recursively<Recursively<Recursively<string>>>();
Console.WriteLine(recursively.Instance.GetType().ToString());
Console.Writeline(recursively.Instance.Instance.GetType().ToString());
Console.Writeline(recursively.Instance.Instance.Instance.GetType().ToString());

Answer 2

也许，使用对象？

AudienceOperators<object> op3 = new AudienceOperators<object>(new List<object> { op1, op2 }, "AND");

你不必宣布IAudienceOperators。

不使用接口的递归泛型类声明

2 个答案: