从java代码执行2个python脚本,一个脚本作为参数传递

时间:2015-08-12 06:16:23

标签: java python-3.x processbuilder

我有一个python scriptA,它调用另一个python scriptB的函数b。我可以在scriptA中导入scriptB,然后在python中使用scriptB.b调用该函数。

但是我想使用process builder和scriptA从java执行函数scriptB.b.我将scriptB路径作为参数传递,但无法加载模块。

我的Java代码

String pbCommand[] = { python3Path,"scriptAPath/scriptA.py","--scriptB","scriptBPath/scriptB.py"};

        ProcessBuilder pb = new ProcessBuilder(pbCommand);
        Process p = pb.start();
        InputStream is = p.getInputStream();
        InputStreamReader isr = new InputStreamReader(is);
        BufferedReader br = new BufferedReader(isr);
        while ((line = br.readLine()) != null) {
                System.out.println("Python Output: " + line);           
            }

Python ScriptA

def get_opts():
    parser = OptionParser()
    parser.add_option("-s", "--scriptB", dest="s",help="the second python script to be used")
    (options, args) = parser.parse_args()
    return (options, args) 


def run():
    (options, args) = get_opts()   
    print "test1"
    scriptB_path=options.s
    scriptb_module = imp.load_source('scriptB', scriptB_path)
    scriptb_module.b()
    print "test2"

if __name__ == '__main__':
    run()

我得到test1因此进程构建器正确执行初始python脚本A,正确解析参数并为scriptB提供正确的路径但是它无法调用函数scriptB.b。我认为问题在于它无法将scriptB作为模块导入,因为它是作为参数传递的。

0 个答案:

没有答案