Question

我有一个存储在$finalvendorid中的数组，看起来像这样

Array
(
    [0] => Array
        (
            [id] => 14
            [vendorid] => 26
            [area] => N1
        )

    [1] => Array
        (
            [id] => 13
            [vendorid] => 33
            [area] => N1
        )

    [2] => Array
        (
            [id] => 15
            [vendorid] => 37
            [area] => N1
        )

)

从此我需要获取vendorid并显示其数据。我试图使用foreach循环然后显示数据，我正确地获得了数据，但我无法按升序显示它（根据avgrating）

供应商表的演示视图是

id  vendorname  vendordesc  avgrating
26    V1            VD1        2            
33    V2            VD2        3            
37    V3            VD3        1

循环代码

<?php
foreach ($finalvendorid as $keyy => $valuee)
    {
        $newvendorid =  $valuee['vendorid'];        
        $sql01 = "SELECT * FROM vendor where id='".$newvendorid."' ORDER BY avgrating ASC";
        //echo $sql01;
        $result01 = mysqli_query($con, $sql01);
        if (mysqli_num_rows($result01) > 0) 
            {
                while($row01 = mysqli_fetch_assoc($result01)) 
                    {
                        //displaying of data 
                    }
            }
    }
?>

任何人都可以告诉我如何按照asc顺序排列数据，以便按以下顺序获得o / p供应商

first vendor with id 37 should get displayed, 
then vendor with id 26 should get displayed and 
finally vendor with id 33 should get displayed

Answer 1

替换

ORDER BY avgrating DESC

与

ORDER BY avgrating

Answer 2

试试这个

<?php
    foreach ($finalvendorid as $keyy => $valuee)
    {
        $newvendorid =  $valuee['vendorid'];        
        $sql01 = "SELECT * FROM vendor where id='".$newvendorid."' ORDER BY   avgrating DESC";
        echo $sql01;
        $result01 = mysqli_query($con, $sql01);
        if (mysqli_num_rows($result01) > 0) 
            {
                while($row01 = mysqli_fetch_assoc($result01)) 
                    {
                        //displaying of data 
                    }
            }
    }
?>

Answer 3

尝试使用此代码可以解决您的问题：

<?php
$ids=array(); $v_ids=null;

/*get vendore id and store in ids array*/
foreach($finalvendorid as $key => $value){
    $ids[] = $value['vendorid'];
}

if(count($ids) > 0){
    /* make string of all vendore id seperated by comma */
    $v_id = implode(",",$ids);

    /*start your query here with order by clause */
    $sql01 = "SELECT * FROM vendor where id IN($v_id) ORDER BY avgrating ASC";
        //echo $sql01;
        $result01 = mysqli_query($con, $sql01);
        if (mysqli_num_rows($result01) > 0) 
            {
                while($row01 = mysqli_fetch_assoc($result01)) 
                    {
                        //displaying of data 
                    }
            }

}
?>

数据未在foreach循环内以asc顺序显示

3 个答案: