Question

我有一个如下所示的数组......

int salesNum;
char lastName[100];
char firstName[50];
int salesLevel;
double salesAmount;

char oneline[200];
while(fgets(oneline, sizeof oneline, fPointer) != NULL) {
  char sentinel;
  if (5 != sscanf(oneline,"%d : %99[^:]: %49[^:]:%d :%lf %c",
      &salesNum, lastName, firstName, &salesLevel, &salesAmount, &sentinel)) break;
  printf("%d , '%s' , '%s' , %d , %lf\n",  
      salesNum, lastName, firstName, salesLevel, salesAmount);
}

我觉得这很难解释，但是我想把这个数组分解为仅显示没有重复的简化URL，所以它看起来像这样......

$urls = array(
    "http://www.google.com",
    "http://www.google.com/maps",
    "http://www.google.com/mail",
    "https://drive.google.com",
    "https://www.youtube.com",
    "https://www.youtube.com/feed/subscriptions",
    "https://www.facebook.com/me",
    "https://www.facebook.com/me/friends"
);

请注意，第二个数组中的最后一个URL仍然有它的路径。这是因为我还想要显示最低级别的路径

Answer 1

基于@Tim的回答

foreach ($urls as &$url) {
    $url_parts = parse_url($url);
    $url = $url_parts["scheme"]."://".$url_parts["host"];
}

$urls = array_unique($urls);

Answer 2

只需按相反的顺序对数组进行排序，然后创建一个由host：

索引的数组

$urls = array(
    "http://www.google.com",
    "http://www.google.com/maps",
    "http://www.google.com/mail",
    "https://drive.google.com",
    "https://www.youtube.com",
    "https://www.youtube.com/feed/subscriptions",
    "https://www.facebook.com/me",
    "https://www.facebook.com/me/friends"
);

rsort($urls);

$return = []; 
foreach($urls as $url) {
        $host = parse_url($url, PHP_URL_HOST);
        $return[$host] = $url;
}
$return = array_values($return); // To remove array keys, if desired.

反向排序的urls数组将是：

Array
(
    [0] => https://www.youtube.com/feed/subscriptions
    [1] => https://www.youtube.com
    [2] => https://www.facebook.com/me/friends
    [3] => https://www.facebook.com/me
    [4] => https://drive.google.com
    [5] => http://www.google.com/maps
    [6] => http://www.google.com/mail
    [7] => http://www.google.com
)

由于排序数组中的最后一个条目（每个主机名）是您想要的，并且它故意破坏任何现有的数组值，因此会输出：

Array
(
    [www.youtube.com] => https://www.youtube.com
    [www.facebook.com] => https://www.facebook.com/me
    [drive.google.com] => https://drive.google.com
    [www.google.com] => http://www.google.com
)

Answer 3

试试这个：

$result = array();
array_push($result, $urls[0])
for($i=1; $i<count($urls); $i++)
{
    $repeat = false;
    foreach($result as $res)
    {
        if(strpos($urls[i], $res))
        {
            $repeat = true;
            break;
        }
    }
    if(!repeat)
       array_push($result, $urls[i])
}

return $result;

减少没有重复的URL字符串

3 个答案: