Question

我正在尝试计算我们的技术人员使用的产品数量

表格设置为

count1，size1，count2，size 2

$sql="select SUM(count1) AS count1, size1, SUM(count2) AS count2, size2 FROM PARTS WHERE crew='$crew' GROUP BY size1 ORDER BY size1 DESC";

可以工作，但显示为两个单独的列，我必须手动将两者一起添加。我试过的时候：

$sql="select SUM(count1) AS count1, size1, SUM(count2) AS count1, size2 AS size1 FROM PARTS WHERE crew='$crew' GROUP BY size1 ORDER BY size1 DESC";

我收到错误：组声明中的列'size1'不明确。我该怎么办？

Answer 1

这是你的意思吗？

$sql="select SUM(count1 + count2) AS count, size1 FROM PARTS WHERE crew='$crew' GROUP BY size1 ORDER BY size1 DESC";

Answer 2

假设两个大小的列都是可互换的，您可以将每个零件大小的所有两个查询合并，然后应用sum计算：

SELECT   size, SUM(cnt)
FROM     (SELECT size1 AS size, count1 AS cnt FROM parts WHERE crew='$crew'
          UNION ALL
          SELECT size2 AS size, count2 AS cnt FROM parts WHERE crew='$crew') t
GROUP BY size
ORDER BY size DESC

连接多个列相同的表

2 个答案: