Question

找出列表中每个项目的对象类型的最佳方法是什么？

我一直在使用下面但它非常麻烦，并且需要知道对象类型以便能够测试它。

for form in form_list:

    if type(form) is list:
        print 'it is a list'
    else:
        print 'it is not a list'

    if type(form) is dict:
        print 'it is a dict'
    else:
        print 'it is not a dict'              

    if type(form) is tuple:
        print 'it is a tuple'
    else:
        print 'it is not a tuple' 

    if type(form) is str:
        print 'it is a string'
    else:
        print 'it is not a string'             

    if type(form) is int:
        print 'it is an int'
    else:
        print 'it is not an int'

Answer 1

在Python 2.7中：

form_list = ['blah', 12, [], {}, 'yeah!']
print map(type, form_list)

[str, int, list, dict, str]

在Python 3.4中：

form_list = ['blah', 12, [], {}, 'yeah!']
print(list(map(type, form_list)))

[<class 'str'>, <class 'int'>, <class 'list'>, <class 'dict'>, <class 'str'>]

Answer 2

知道python中的类型通常不是理想的方式。如果您对此不熟悉，请阅读duck-typing主题。

如果您仍想沿着这条路走下去，请执行以下操作：

objtype = type(form)
if objtype is list:
    #do stuff
elif objtype is str:
    #do other stuff
else:
    #can't handle this

等等

找出列表中每个项目的对象类型的最佳方法

2 个答案: