Question

我正在创建一台退货率约为95％的老虎机。但我觉得我经常赢得比赛。谁能证实这一点？老虎机有3个旋转器（卷轴），每个旋转器有4个不同的符号。获胜的机会应该是：

3x符号[1]：23.6％几率（第一个旋转器为50％，第二个为80％，第三个为59％）

3x符号[2]：9.45％几率（第一个旋转器为25％，第二个为70％，第三个为54％）

3x符号[3]：1.89％几率（第一个旋转器为15％，第二个为60％，第三个为21％）

3x符号[4]：0.19％几率（第一个旋转器为10％，第二个为50％，第三个为3.8％）

local symbol = {} 
symbol[1] = {0.5, 0.8, 0.59}
symbol[2] = {0.5, 0.7, 0.54} 
symbol[3] = {0.6, 0.6, 0.21} 
symbol[4] = {1, 0.5, 0.038}

function chance(x) 
    if math.random() <= x then 
        return true
    end 
end

-- FIRST SPINNER
for i = 1, 4 do 
    if chance(symbol[i][1]) then
        stop[1] = symbol[i] 
        break
    end
end

-- SECOND SPINNER
for i = 1, 4 do 
    if stop[1] == symbol[i] then
        if chance(symbol[i][2]) then
            stop[2] = symbol[i]
        else
            -- stop[3] = some random symbol that is not equal to stop[1]
        end
        break
    end
end 

-- THIRD SPINNER
for i = 1, 4 do 
    if stop[1] == symbol[i] and stop[2] == symbol[i] then
        if chance(symbol[i][3]) then
            stop[3] = symbol[i]
        else
            -- stop[3] = some random symbol that is not equal to stop[2]
        end 
    end
end

if stop[3] == nil then
    -- stop[3] = some random symbol that is not equal to stop[2]
end

-- WIN SCRIPT
if stop[1] == stop[2] and stop[2] == stop[3] then
   -- reward player
end

Answer 1

local symbol = {}
symbol[1] = {0.5, 0.8, 0.59}
symbol[2] = {0.5, 0.7, 0.54}
symbol[3] = {0.6, 0.6, 0.21}
symbol[4] = {1, 0.5, 0.038}

function chance(x)
   return math.random() <= x
end

-- FIRST SPINNER
for _, sym in ipairs(symbol) do
   stop[1] = sym
   if chance(sym[1]) then break end
end

-- SECOND SPINNER
if chance(stop[1][2]) then
   stop[2] = stop[1]
   -- THIRD SPINNER
   if chance(stop[1][3]) then
      stop[3] = stop[1]
   else
      -- stop[3] = some random symbol that is not equal to stop[1]
      repeat
         stop[3] = symbol[math.random(4)]
      until stop[3] ~= stop[1]
   end
else
   -- stop[2], stop[3] = some random symbols, not both equal to stop[1]
   repeat
      stop[2] = symbol[math.random(4)]
      stop[3] = symbol[math.random(4)]
   until stop[2] ~= stop[1] or stop[3] ~= stop[1]
end

-- WIN SCRIPT
if stop[1] == stop[2] and stop[2] == stop[3] then
   -- reward player
end

老虎机赢得机会的方式太高了

1 个答案: