在linq中展平列表

Question

让我们假设我的列表是这样的：

List<List<string>> zz = new List<List<string>>() { new List<string>{"1","2","3"}, new List<string> { "4", "5", "6" } };

我想要一个列表作为输出，如下所示：

List<string> finalList = new List<string>{"1","2","3","4", "5", "6"};

如何展平？

Answer 1

您可以使用SelectMany

var finalList = zz.SelectMany(x=>x).ToList();

Answer 2

var finalList = zz.SelectMany(a => a).ToList();