Question

我有一个简单的PHP代码，它从数据库中检索数据并以json格式显示，如下所示

[

{
S.no: "1",

News: "http://bbau.ac.in/Office%20Notice/off%20note/Aug15/1766.pdf",

Date: "2015-08-11",

news_desc: "Minute to Minute Programme on 15th August"

},

{
S.no: "2",

News: "http://bbau.ac.in/Office%20Notice/off%20note/Aug15/1760.pdf",

Date: "2015-08-11",

news_desc: "Sub - committee to look into the all sign boards of the buildings"

}

]

但是我想把这个结果放在一个数组中，这样我的json输出应该是

News:[

  {
S.no: "1",

News: "http://bbau.ac.in/Office%20Notice/off%20note/Aug15/1766.pdf",

Date: "2015-08-11",

news_desc: "Minute to Minute Programme on 15th August"

},

{

S.no: "2",

News: "http://bbau.ac.in/Office%20Notice/off%20note/Aug15/1760.pdf",

Date: "2015-08-11",

news_desc: "Sub - committee to look into the all sign boards of the buildings"

}

]

我正在粘贴下面的php代码：

 <?php

$con=$con=@mysql_connect("localhost","root","");
if(!$con)
    {
        die('Could not connect'.mysql_error());
    }
mysql_select_db("mysql",$con);
$result=mysql_query("Select * from bbau_news");
$array=array();
while($row=mysql_fetch_assoc($result))
    {
        $output[]=$row;
    }
print(json_encode($output));
mysql_close($con);

?>

请帮助我，因为我是JSON和PHP的新手

Answer 1

更改

$output[]=$row;

要

$output['News'][]=$row;

这应该提供你想要的输出。

Answer 2

从

改变

print(json_encode($output));

要

print(json_encode(array('News', $output)));

Answer 3

$output['News']=array();
while($row=mysql_fetch_assoc($result))
    {
        $output['News'][]=$row;
    }

试试这个。它会起作用。

谢谢你：）

Answer 4

为此，您需要首先json_decode来自DB的JSON

$jsonArray = json_decode( $row['json'], true );  //true will give array else it will give object

然后

$output[] = json_encode( array( 'News', $jsonArray ) );

然后$ output将具有您需要的格式。

从数据库中获取json格式的obejct

4 个答案: