Question

我正在使用Objective-C在iOS上制作匹配游戏有一组12张卡片（3列4行）是UIButton连接到IBOutletCollection的数组，问题是当你点击第一张卡片时，你也可以同时点击其他卡片，但要点击的允许卡必须只有2张卡。如果分接的卡大于1且小于2，我该如何防止卡的敲击。

Answer 1

//One action for all buttons
-(void)buttonAction:(UIButton*)button
{

//if user select three button at a time, dont do further operations
if (previousButton && currentButton) {
    return;
}

//previous button is the first button
if(previousButton==nil)
{
    previousButton=button;
}
//current button is the second button
else if(currentButton==nil)
{
    currentButton=button;
}
//if button is selected, set button as not selected and vice versa
if([button isSelected]==NO)
{
    [button setSelected:YES];
}
else
{
    [button setSelected:NO];
}
//if user press the same button again and again
if (currentButton==previousButton)
{
    currentButton=nil;
    if([previousButton isSelected]==NO)
    {
        previousButton=nil;
    }
    return;
}    
  else if((currentButton!=previousButton)&&(currentButton!=nil))
{
    //both button tags are same, that means both selected state images are same
    if(previousButton.tag==currentButton.tag)
    {
        [self performSelector:@selector(delay) withObject:nil afterDelay:0.5];
    }
    else
    {
        [self performSelector:@selector(delayTwo) withObject:nil afterDelay:0.5];
    }
 } 
 }

-(void)delay
 {
    //[currentButton setHidden:YES];
    //[previousButton setHidden:YES];
  currentButton=nil;
previousButton=nil;
score++;
NSLog(@"Score %d",score);
//the final stage, that means left only two buttons
if(score==6)
{
    //[self endGame];
  }
 } 

-(void)delayTwo
{
   [currentButton setSelected:NO];
   [previousButton setSelected:NO];
  currentButton=nil;
  previousButton=nil;
}

在viewDidLoad中，指定所有选中的按钮＆amp;您需要的正常状态图像或标题

Answer 2

我不是100％肯定你在这里得到了什么，但你可以尝试使用多个UITapGestureRecognizer实例。你可以有一个用于1个点击，一个用于2，一个用于3+。这样，您可以选择1或2个触摸卡，但如果有3个或更多，则忽略它。

如何在iOS中的NSArray中获取未选中的数组

2 个答案: