Question

我一直坚持这个错误。你能否在下面的代码中说明错误是什么？这是在为变量输入的过程中编写的。感谢。

execute immediate 'Create or replace view '||p_viewname||' AS  
     select * from (  
     select NAME, CODETYPE, CODE  
     from HLIDEV_VIEWS.V_CONCEPT  
     WHERE HLIDEV_VIEWS.V_CONCEPT.CONCEPTTYPE = '''||p_concepttype||'''  
    )  
    pivot   
    (  
       max(code)  
       for codetype in ('||all_codetypes||')  
    )';

更新：以下是我看到的错误。

EXEC "HLIDEV_VIEWS"."FinalCreatePOAView" ('POA_CONCEPT_TYPE','PresentOnAdmission')
Error report -
ORA-00911: invalid character
ORA-06512: at "HLIDEV_VIEWS.FinalCreatePOAView", line 39
ORA-06512: at line 1
00911. 00000 -  "invalid character"
*Cause:    identifiers may not start with any ASCII character other than
           letters and numbers.  $#_ are also allowed after the first
           character.  Identifiers enclosed by doublequotes may contain
           any character other than a doublequote.  Alternative quotes
           (q'#...#') cannot use spaces, tabs, or carriage returns as
           delimiters.  For all other contexts, consult the SQL Language
           Reference Manual.
*Action:

Answer 1

使用execute immediate完全可以做到的。你只是在某处有语法错误，或者表格确实不存在。

尝试将您正在构建的字符串写入DBMS_OUTPUT.PUT_LINE，而不是将其发送到EXECUTE IMMEDIATE。然后，尝试在SQL * Plus中将该字符串作为命令运行。这应该突出错误。

FWIW，我的数据库中没有你的对象，但是我写了一个与你的相同格式的EXECUTE IMMEDIATE，它在Oracle 11g2中工作正常。

DECLARE  
  p_view_name VARCHAR2(61) := 'VXSMIMMCP.MATT_V';
  p_region_code VARCHAR2(30) := 'R01';
  p_all_port_codes VARCHAR2(400) := '''P01'',''P02'',''P03''';
BEGIN
  EXECUTE IMMEDIATE
       'Create or replace view '
    || p_view_name
    || ' AS select * from ( select REGION_CODE,   account_number , port_code from APPS.XXCUS_ACCOUNTS WHERE APPS.XXCUS_ACCOUNTS.REGION_CODE  = '''
    || p_region_code
    || ''' ) pivot ( min(account_number) for port_code in ('
    || p_all_port_codes
    || ') )' ;
END;

Answer 2

感谢@MatthewMcPeak和@MahendarMahi的意见。突然，我的代码开始正常工作，它以我想要的方式创建了视图。我唯一做的是，正如@MahendarMahi建议的那样，我移除了枢轴并运行它以查看相同的错误，然后更换了枢轴，错误消失了。我确信代码没有变化，但无论如何它现在都很奇怪。再次感谢你的时间。

立即执行＆＃39;创建或替换视图＆＃39;给出00900. 00000 - ＆＃34;无效的SQL语句＆＃34;错误

2 个答案: