MySQL分析功能

Question

我有一张格式低于表格的表

SurveyCity ProductName SurveybyCompany1 SurveybyCompany2
City1      Chocolate     Good           Good
City1      Caramel       Good           Bad
City1      Vanilla       Bad            Good
City1      Butterscoth   Bad            Bad
City2      Chocolate     Good           Good
City2      Caramel       Good           Bad
City2      Vanilla       Bad            Good
City2      Butterscoth   Bad            Bad

我想要一份这样的报告

Company1    Company2    Caramel Chocolate Vanilla Butterscoth   
Good        Good        0          2        0       0
Good        Bad         2          0        0       0
Bad         Good        0          0        2       0
Bad         Bad         0          0        0       2

我正在写下面的4个查询来生成此报告

select productname,count(*) from table where surveybycompany1='Good' and surveybycompany2='Good' group by productname

我的疑问是，是否可以在一个查询中生成整个输出表。我正在使用MySQL DB

请提供您宝贵的建议

Answer 1

您可以使用sum，if和group by

select SurveybyCompany1 Company1, 
SurveybyCompany2 Company2, 
sum(if(ProductName = 'Caramel', 1, 0)) as Caramel, 
sum(if(ProductName = 'Chocolate', 1, 0)) as Chocolate, 
sum(if(ProductName = 'Vanilla', 1, 0)) Vanilla, 
sum(if(ProductName = 'Butterscoth', 1, 0)) Butterschoth 
from your_table group by Company1, Company2
order by Company1 desc, Company2 desc;

输出：

+----------+----------+---------+-----------+---------+--------------+
| Company1 | Company2 | Caramel | Chocolate | Vanilla | Butterschoth |
+----------+----------+---------+-----------+---------+--------------+
| Good     | Good     |       0 |         2 |       0 |            0 |
| Good     | Bad      |       2 |         0 |       0 |            0 |
| Bad      | Good     |       0 |         0 |       2 |            0 |
| Bad      | Bad      |       0 |         0 |       0 |            2 |
+----------+----------+---------+-----------+---------+--------------+