Question

这里似乎有很多问题，但没有人帮助我.... 尝试使用单个Java Class作为运行嵌入式Jetty和Jersey的起始点，以提供Webpages和JSON接口......但是，即使第一步也未能提供多个页面。

这很好用

ServletHolder jerseyServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*");
jerseyServlet.setInitOrder(0);      
jerseyServlet.setInitParameter("jersey.config.server.provider.classnames", EntryPoint.class.getCanonicalName());

但添加其他内容失败。如何提供提供不同内容类型的多个页面？是在单个EntryPoint类中添加内容的唯一解决方案吗？

提前感谢任何暗示需要更改

的内容

public class App {
public static void main(String[] args) throws Exception {
    ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
    context.setContextPath("/");
    Server jettyServer = new Server(8080);
    jettyServer.setHandler(context);

    ServletHolder jerseyServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*");
    jerseyServlet.setInitOrder(0);                                                                                  
    jerseyServlet.setInitParameter("jersey.config.server.provider.classnames", EntryPoint.class.getCanonicalName());

    ServletHolder helloWorldServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*");
    helloWorldServlet.setInitOrder(1);                                                                                  
    helloWorldServlet.setInitParameter("jersey.config.server.provider.classnames", HelloWorldService.class.getCanonicalName());

    try {
        jettyServer.start();
        jettyServer.join();
    } catch (Exception e){
        System.out.println("Failed running jettyServer with " + e.getMessage());
    } finally {
        jettyServer.destroy();
    }
}

}

Answer 1

实际上找到了解决方案。缺少密钥信息是你只需要每一个和所有正确的处理程序，把它们放在一个处理程序列表中，瞧你在那里....

主要是在找到它后从码头文件中取出

public class JettyServer
{
public static void main(String[] args) throws Exception
{
    // Create a basic Jetty server object that will listen on port 8080.  Note that if you set this to port 0
    // then a randomly available port will be assigned that you can either look in the logs for the port,
    // or programmatically obtain it for use in test cases.
    Server server = new Server(8080);

    // Create the ResourceHandler. It is the object that will actually handle the request for a given file. It is
    // a Jetty Handler object so it is suitable for chaining with other handlers as you will see in other examples.
    ResourceHandler resource_handler = new ResourceHandler();
    // Configure the ResourceHandler. Setting the resource base indicates where the files should be served out of.
    // In this example it is the current directory but it can be configured to anything that the jvm has access to.
    resource_handler.setDirectoriesListed(true);
    resource_handler.setWelcomeFiles(new String[]{ "./html/index.html" });
    resource_handler.setResourceBase(".");

    //Jersey ServletContextHandler
    ServletContextHandler servletContextHandler = new ServletContextHandler(ServletContextHandler.SESSIONS);
    ServletHolder jerseyServlet = servletContextHandler.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/api/*");
    jerseyServlet.setInitOrder(0);                                                                                  
    jerseyServlet.setInitParameter("jersey.config.server.provider.classnames", EntryPoint.class.getCanonicalName());

    // Add the ResourceHandler to the server.
    HandlerList handlers = new HandlerList();
    handlers.setHandlers(new Handler[] { resource_handler, servletContextHandler, new DefaultHandler() });
    server.setHandler(handlers);

    // Start things up! By using the server.join() the server thread will join with the current thread.
    // See "http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Thread.html#join()" for more details.
    server.start();
    server.join();
}

}

帮了我......

Answer 2

我认为这就是你想要的：

jerseyServlet.setInitParameter("jersey.config.server.provider.classnames",
             String.join(",", Arrays.asList(EntryPoint.class.getCanonicalName(),
                     HelloWorldService.class.getCanonicalName())));

Answer 3

您没有将ServletHolder个实例添加到ServletContextHandler。

这两个servlet也有相同的/*路径，我不确定但是这可能不起作用，尝试归因于不同的路径并查看它是否有效。

执行：

context.addServlet（jerseyServlet，“/ jersey”）;

context.addServlet（helloWorldServlet，“/ hello”）;

错误“多个servlet映射到路径：/ *：”在嵌入式Jetty中使用jerseyServlets

3 个答案: