Question

对于Python 2.7：

vTest = Source.objects.get(id=self.id).state

有没有办法让我更轻松？类似的东西：

$stateParam

Answer 1

尝试

self.assertTrue(all(x in list1 for x in [1,2]))

如果可以使用pytest-django，则可以使用本机断言语句：

assert all(x in in list1 for x in [1,2])

Answer 2

我确定你已经弄明白但是你可以使用循环：

tested_list = [1, 2, 3]
checked_list = [1, 2]

# check that every number in checked_list is in tested_list:
for num in checked_list:
    self.assertIn(num, tested_list)

这对tested_list中缺少的特定号码失败，因此您可以立即知道问题所在。

Answer 3

对于这样的东西，我特别喜欢hamcrest库。

你可以写下你的测试：

from hamcrest import assert_that, has_items, contains_inanyorder

assert_that([1, 2], has_items(2, 1)) # passes

assert_that([1, 2, 3], has_items(2, 1)) # also passes - the 3 is ignored
assert_that([1, 2], has_items(3, 2, 1)) # fails - no match for 3
assert_that([1, 2], contains_inanyorder(2, 1)) # passes
assert_that([1, 2, 3], contains_inanyorder(2, 1)) # fails, no match for 3

稍微丑陋，可读性较差，但显示所有缺失的元素，而不仅仅是第一个失败的元素：

actual = [1, 2]
expected = set([1, 2, 3, 4])
self.assertEqual(set(actual) & expected, expected)

输出：

AssertionError: Items in the second set but not the first:
3
4

在Python单元测试中是否存在子列表的断言？

3 个答案: