Question

在Symfony2中，我在自定义存储库函数中获得了下一个代码：

    $em = $this->getEntityManager();
    $qb = $em->createQueryBuilder();

    $any = "Jon";

    $qb->select('s')
        ->from('AppBundle:Student', 's');


    if ($criteria) {
        foreach ($criteria as $field => $value) {
            $qb->andWhere($qb->expr()->eq('s.' . $field, $value));
        }
    }

    $qb->andWhere(
        $qb->expr()->orX(
            $qb->expr()->like('s.firstname', ":any"),
            $qb->expr()->like('s.lastname', ":any"),
            $qb->expr()->like('s.dni', ":any"),
            $qb->expr()->like('s.email', ":any")
        )
    );
    if ($offset) {
        $qb->setFirstResult($offset);
    }
    if ($limit) {
        $qb->setMaxResults($limit);
    }

    $query = $qb->getQuery();

    $query->setParameter('any',(string) $any);

    $logger->warning(__METHOD__ . ": " . json_encode($query->getSQL()));

    $result = $query->getResult();

但$ result总是空的。也许是因为$ query-＆gt; getSQL（）总是返回：

"SELECT p0_.id AS id0, p0_.firstname AS firstname1, p0_.lastname AS lastname2, p0_.email AS email3, p0_.dni AS dni4, p0_.phonenumber AS phonenumber5, p0_.active AS active6, p0_.birthdate AS birthdate7, p0_.sex AS sex8, p0_.discr AS discr9 
FROM student s1_ INNER JOIN person p0_ ON s1_.id = p0_.id 
WHERE p0_.active = 1 AND (p0_.firstname LIKE ? OR p0_.lastname LIKE ? OR p0_.dni LIKE ? OR p0_.email LIKE ?) LIMIT 15"

问题是，如果我拼错了参数名称，它会抛出异常，因此$ query-＆gt; setParameter行正在执行。它只是......不工作：S

更新1：

有人建议它可能是由重复使用的相同参数引起的。我将代码更新为：

 (...)
    $qb->andWhere(
            $qb->expr()->orX(
                $qb->expr()->like('s.firstname', ":fn"),
                $qb->expr()->like('s.lastname', ":ln"),
                $qb->expr()->like('s.dni', ":dni"),
                $qb->expr()->like('s.email', ":email")
            )
        );
    (...)
        $query = $qb->getQuery();
        $query->setParameters(array('fn' => $any, 'ln' => $any, "dni" => $any, "email" => $any));

没有变化。：其中

更新2：

尝试

$qb->setParameters(array('fn' => $any, 'ln' => $any, "dni" => $any, "email" => $any));

$query = $qb->getQuery();

$logger->warning(__METHOD__ . ": " . json_encode($query->getSQL()));

......没有变化。

更新3：

按建议调试参数：

代码：

$query = $qb->getQuery();

$parameters = $qb->getQuery()->getParameters()->toArray();
foreach ($parameters as $parameter) {
        $logger->warning(__METHOD__ . ": Parameter -> ".json_encode($parameter->getName())." = ".json_encode($parameter->getValue()));
    }
$logger->warning(__METHOD__ . ": " . json_encode($query->getSQL()));

日志：

 app.WARNING: AppBundle\Entity\StudentRepository::findByAny: Parameter -> "fn" = "Jon" [] []
 app.WARNING: AppBundle\Entity\StudentRepository::findByAny: Parameter -> "ln" = "Jon" [] []
 app.WARNING: AppBundle\Entity\StudentRepository::findByAny: Parameter -> "dni" = "Jon" [] []
 app.WARNING: AppBundle\Entity\StudentRepository::findByAny: Parameter -> "email" = "Jon" [] []
 app.WARNING: AppBundle\Entity\StudentRepository::findByAny: "SELECT p0_.id AS id0, p0_.firstname AS firstname1, p0_.lastname AS lastname2, p0_.email AS email3, p0_.dni AS dni4, p0_.phonenumber AS phonenumber5, p0_.active AS active6, p0_.birthdate AS birthdate7, p0_.sex AS sex8, p0_.discr AS discr9 FROM student s1_ INNER JOIN person p0_ ON s1_.id = p0_.id WHERE p0_.active = 1 AND (p0_.firstname = ? OR p0_.lastname = ? OR p0_.dni = ? OR p0_.email = ?) LIMIT 15" [] []

仍然没有结果，SQL仍显示“？”。虽然我认为我发现了错误......

Answer 1

我建议您使用数字参数名称，然后拨打setParameters而不是setParameter。

$qb->andWhere(
    $qb->expr()->orX(
        $qb->expr()->like('s.firstname', "?0"),
        $qb->expr()->like('s.lastname', "?1"),
        $qb->expr()->like('s.dni', "?2"),
        $qb->expr()->like('s.email', "?3")
    )
);

$qb->setParameters([
    'first name', 
    'last name', 
    'user dni', 
    'user.email@gmail.com'
]);

另一种选择可能是：

$qb->andWhere(
    $qb->expr()->orX(
        $qb->expr()->like('s.firstname', ":fn"),
        $qb->expr()->like('s.lastname', ":ln"),
        $qb->expr()->like('s.dni', ":dni"),
        $qb->expr()->like('s.email', ":email")
    )
)

$qb->setParameter('fn', 'first name');
$qb->setParameter('ln', 'last name');
$qb->setParameter('dni', 'user dni');
$qb->setParameter('email', 'user email');

编辑：刚刚检查过，添加了Artamiel提到的相同参数。

Answer 2

...所以我想出来了（当然，在评论中提供了很多帮助）。这很简单，但它让我花了好几个小时。发生这种情况时，你不讨厌吗？

它不起作用，因为当你设置像

这样的参数时

$qb->expr()->like('s.firstname', ":fn")
$qb->setParameters(array('fn' => $any));

您必须手动包含％字符：

    $any = "%Jon%";

而不是

    $any = "Jon";

当然，这是有道理的。您可能只想要其中一个边的％字符。

很有意义的是， $ query-＆gt; getSQL（）仍然不会显示参数（仅限＆＃34;？＆＃34;字符）即使参数链接到QueryBuilder而不是Query本身，所以它就像：＆＃34;重点是什么？＆＃34;。

道德：不要相信Query-＆gt; getSQL（）用于调试目的。几乎无用。

特别赞助用户@Artamiel

Doctrine Query-＆gt; getSQL（）不输出任何参数

2 个答案: