Question

我有一个带有ipaddresses的文本字段，但现在允许把ipaddress放在：127或192开头。我有这个：

foreach (var item in lines)
{
    if (item.StartsWith("127") || item.StartsWith("192"))
    {
        foreach (var result in lines)
        {
            //lines[result].ToString()
            result.ToString();   
            return new ValidationResult("Some Ip Address(ses) are not correct" + "\n" + result.ToString() );

        }
        // return new ValidationResult("IpAddress cant be saved");   
    }
    if (String.IsNullOrWhiteSpace(IpCondition.IpAddress))
        return new ValidationResult(this.FormatErrorMessage(validationContext.DisplayName));

    IPAddress address;

    if (IPAddress.TryParse(item, out address))
        continue;
    else
        return new ValidationResult("IpAddress cant be saved");                
}

但问题是，如果你在文本字段中输入：127和192，你只会看到：127而不是192错误的ipaddress。

我现在就这样：

IpConditionSettings IpCondition = validationContext.ObjectInstance as IpConditionSettings;

string[] lines = IpCondition.IpAddress.Split(new string[] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries);
lines = IpCondition.IpAddress.Split(new char[0], StringSplitOptions.RemoveEmptyEntries);
var resultsValidation = new List<ValidationResult>();

foreach (var item in lines)
{
    var result = lines.Where(x => x.StartsWith("127") || x.StartsWith("192"));
    if (result.Any())
        return new ValidationResult("Some Ip Address(ses) are not correct", result);

    if (String.IsNullOrWhiteSpace(IpCondition.IpAddress))
        return new ValidationResult(this.FormatErrorMessage(validationContext.DisplayName));

    IPAddress address;
    if (IPAddress.TryParse(item, out address))
        continue;
    else
        return new ValidationResult("IpAddress cant be saved");
}

但现在它没有显示错误信息。

如何拥有这件作品：

 if (IPAddress.TryParse(item, out address))
     continue;
 else
     return new ValidationResult("IpAddress cant be saved");

错误的IP地址？

Answer 1

您可以使用linq查询来获取无效地址。

var result = lines.Where(x => x.StartsWith("127") || x.StartsWith("192"));

然后使用ValidationResult(String, IEnumerable<String>)构造函数返回结果。

if(result.Any())
    return new ValidationResult("Some IP-address(es) are not correct.", result);

或者，如果您想在单个字符串中返回它们，可以使用String.Join()。

if(result.Any())
    return new ValidationResult("Some IP-address(es) are not correct.\n" + String.Join(", ", result));

显示更多错误消息

1 个答案: