我有一个列表,其中向用户显示了一些选项。我还有两个按钮用于下一个和上一个。接下来,新的选项将从数据库中绑定。
问题:
按下上一个按钮,我想显示之前选择的状态。可悲的是,我无法突出显示所选行。
listviewoptions = (ListView)findViewById(R.id.lstviewoptionAptitude);
listviewoptions.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> arg0, View arg1,int position ,
long arg3) {
if (previouslySelectedItem != null)
{
previouslySelectedItem.setBackgroundColor(Color.TRANSPARENT);
//getResources().getColor(R.color.pressed_color));
}
String Selectedcolor = "#fdc500";
arg1.setBackgroundColor(Color.parseColor(Selectedcolor));
// getResources().getColor(R.color.default_color));
previouslySelectedItem = arg1;
// TODO Auto-generated method stub
Toast.makeText(getApplicationContext(),"programitically Clicked", Toast. LENGTH_SHORT).show();
response = position+1;
}
});
功能GetPrevious选择选项
public void getoptionSelected(Integer StudentIDResponse , String QuestionIDResponse)
{
SQLiteDatabase db = helper.getReadableDatabase();
Cursor c = null;
String selectQuestion = "Select * from TableResponse where StudentID = "+StudentIDResponse+" AND QuestionID ="+QuestionIDResponse;
c = db.rawQuery(selectQuestion, null);
if( c.getCount() >0) {
if (c.moveToFirst()) {
do {
strOptionResponseID = c.getString(c.getColumnIndex("QuestOptionID"));
} while (c.moveToNext());
}
}
else
{
//No response Found
}
}
我在之前的按钮上尝试了什么
public void PrevQuestion()
{
getoptionSelected(StudentID,QuestionID);
if (strOptionResponseID !=null)
{
**1st Method I tried**
response = Integer.parseInt(strOptionResponseID);
listviewoptions.performItemClick(
listviewoptions.getAdapter().getView(response, null, null),
response,
listviewoptions.getAdapter().getItemId(response));
**2nd Method I tried**
listviewoptions.performItemClick(listviewoptions.getAdapter().getView(3, null, null), 3, listviewoptions.getItemIdAtPosition(3));
listviewoptions.setSelection(response);
listviewoptions.getSelectedView().setSelected(true);
}
更新
public class ListAdapter extends ArrayAdapter<Item> {
public ListAdapter(Context context, int textViewResourceId) {
super(context, textViewResourceId);
}
public ListAdapter(Context context, int resource, List<Item> items) {
super(context, resource, items);
}
public View getView(int position, View convertView, ViewGroup parent) {
View view = super.getView(position, convertView, parent);
if (position == 1)
{
String Selectedcolor = "#fdc500";
// arg1.setBackgroundColor(Color.parseColor(Selectedcolor));
view.setBackgroundColor(Color.parseColor(Selectedcolor));
}
else
{
view.setBackgroundColor(Color.RED);
}
return view;
}
}
答案 0 :(得分:2)
您可以通过两种方式显示选择。
1]将choicemode设置为&#34; SingleChoice&#34; listView并使用自定义&#34; Checkable&#34;查看find here 。
2]覆盖getView()并根据某个成员变量更改背景。
public View getView(int position, View convertView, ViewGroup parent) {
View view = super.getView(position, convertView, parent);
if (this_is_the_selected_item)
{
view.setBackgroundColor(selectedcolor);
}
else
{
view.setBackgroundColor(Normal_color);
}
return view;
}
答案 1 :(得分:0)
第1步
yourlistview.setItemChecked(iposition,true); //这里iposition是选定位置的int
第2步
List<String> options = db.getAllOptions(QuestionID);
ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
R.layout.simple_list_item_activated_1, R.id.text1, options);
listviewoptions.setAdapter(adapter);