我有不同的字符串，包含这样的电话号码：
New order to car wash #663. Customer number is 7962555443. Thank you.
或
New order to car wash #663. Customer number is 50414. Thank you, bye.
或
New order to car wash #663. A phone number to connect with the customer is 905488739038.
我需要这个：
New order to car wash #663. Customer number is 7 9 6 2 5 5 5 4 4 3. Thank you.
或
New order to car wash #663. Customer number is 5 0 4 1 4. Thank you, bye.
或
New order to car wash #663. A phone number to connect with the customer is 9 0 5 4 8 8 7 3 9 0 3 8.
我需要分开包含3个以上符号的数字。
答案 0 :(得分：2)
preg_replace单独没有任何回调函数就足够了。
preg_replace('~#\d+(*SKIP)(*F)|(?<=\d)(?=\d)~', ' ', $str);
#\d+(*SKIP)(*F)匹配并丢弃所有以#开头的数字。|或(?<=\d)(?=\d)现在，从剩余的字符串开始，这将匹配两个数字之间存在的边界。答案 1 :(得分：1)
您可以使用回调：
SELECT
case when Monday ='Y' then'[Mon]' else '' end +case when Monday ='Y' then ',' else '' end +
case when Tuesday ='Y' then'[Tue]' else '' end +case when Tuesday ='Y' then ','else '' end +
case when Wednesday='Y' then'[Wed]' else '' end +case when Wednesday ='Y' then ',' else '' end +
case when Thursday ='Y' then'[Thu]' else '' end +case when Thursday ='Y' then ',' else '' end +
case when Friday ='Y' then'[Fri]' else '' end +case when Friday ='Y' then ',' else '' end +
case when Saturday ='Y' then'[Sat]' else '' end +case when Saturday ='Y' then ',' else '' end +
case when Sunday ='Y' then'[Sun]' else '' end as classday
FROM vw_Class_Without_Instructor
答案 2 :(得分：1)
也可以使用\G anchor来完成此操作。替换为匹配的数字+空格："$0 "
我需要分开包含3个以上符号的数字。
$str = preg_replace('~\b\d(?=\d{3})|\G\d\B~', "$0 ", $str);
\b\d匹配word-boundary \b后跟数字（\d [0-9] (?=\d{3})} \d使用short在第一个|\G\d\B之后检查接下来的3个数字\G或匹配\B 上一场比赛结束时的数字，然后是\h 非字边界 作为替代方案，也可以替换'use strict';
var app = angular.module('myApp', ['app.directives']);
app.controller('AppCtrl', function($scope){
$scope.roles = [
{"id": 1, "name1": "Manager", "assignable": true},
{"id": 2, "name1": "Developer", "assignable": true},
{"id": 3, "name1": "Reporter", "assignable": true}
];
$scope.member = {roles: []};
$scope.selected_items = [];
$scope.displayname = "name1";
});
var app_directives = angular.module('app.directives', []);
app_directives.directive('dropdownMultiselect', function(){
return {
restrict: 'E',
scope:{
model: '=',
options: '=',
displayname: '=',
pre_selected: '=preSelected'
},
template: "<div class='btn-group' data-ng-class='{open: open}'>"+
"<button class='btn btn-small'>Select</button>"+
"<button class='btn btn-small dropdown-toggle' data-ng-click='open=!open;openDropdown()'><span class='caret'></span></button>"+
"<ul class='dropdown-menu' aria-labelledby='dropdownMenu'>" +
"<li><a data-ng-click='selectAll()'><i class='icon-ok-sign'></i> Check All</a></li>" +
"<li><a data-ng-click='deselectAll();'><i class='icon-remove-sign'></i> Uncheck All</a></li>" +
"<li class='divider'></li>" +
"<li data-ng-repeat='option in options'> <a data-ng-click='setSelectedItem()'>{{option[displayname ]}}<span data-ng-class='isChecked(option.id)'></span></a></li>" +
"</ul>" +
"</div>" ,
controller: function($scope){
console.log($scope.displayname );
$scope.openDropdown = function(){
$scope.selected_items = [];
for(var i=0; i<$scope.pre_selected.length; i++){ $scope.selected_items.push($scope.pre_selected[i].id);
}
};
$scope.selectAll = function () {
$scope.model = _.pluck($scope.options, 'id');
console.log($scope.model);
};
$scope.deselectAll = function() {
$scope.model=[];
console.log($scope.model);
};
$scope.setSelectedItem = function(){
var id = this.option.id;
if (_.contains($scope.model, id)) {
$scope.model = _.without($scope.model, id);
} else {
$scope.model.push(id);
}
console.log($scope.model);
return false;
};
$scope.isChecked = function (id) {
if (_.contains($scope.model, id)) {
return 'icon-ok pull-right';
}
return false;
};
}
}
}); 水平空间后的第一个数字：eval.in
答案 3 :(得分：0)
试试这个。
jQuery(statusIcon).attr('src',ICO_ERR);
答案 4 :(得分：0)
您可以使用implode首先使用str_split将字符串转换为数组：
$number="905488739038";
$formatted = implode(' ',str_split($number));
echo $formatted;
输出：
9 0 5 4 8 8 7 3 9 0 3 8
答案 5 :(得分：0)
你也可以试试这个正则表达式：
((?:(?:\d)\s?){4,})
它将捕获长度为四或更长的所有数字。此外，您还需要执行一个额外步骤，从结果中删除匹配中的空格，如下所示：
7 9 6 2 5 5 5 4 4 3