Question

我这里有更新的代码，我的问题是我得到了这种错误＆＃34; SQLSTATE [HY093]：参数号无效：绑定变量的数量与令牌的数量不匹配＆＃34;而且我不知道如何解决这个问题。有人可以帮我解决这个问题吗？

class.user.php

public function update($user_id,$username,$password,$province)
{
try
{
  $stmt=$this->db->prepare("UPDATE login SET username=:username,password=:password,province=:province WHERE user_id=:user_id");
  $stmt->bindparam(":username",$username);
  $stmt->bindparam(":password",$password);
  $stmt->bindparam(":province",$province);
  $stmt->execute();

  return true;
}
catch(PDOException $e)
{
  echo $e->getMessage();
  return false;
}
}

，这是update.php

<?php
include_once 'dbconfig.php';

$username = isset($_GET['username']) ? $_GET['username'] : '';
$password = isset($_GET['password']) ? $_GET['password'] : '';
$province = isset($_GET['province']) ? $_GET['province'] : '';



    if(isset($_POST['btn-update']))
    {
    $user_id = $_GET['user_id'];
    $username = $_POST['username'];
    $password = $_POST['password'];
    $province = $_POST['province'];

    if($crud->update($user_id,$username,$password,$province))
    {
    echo "<script type='text/javascript'>alert('Successfully Updated!');</script>";
    }
    else
    {
    echo "<script type='text/javascript'>alert('Updating Failed!');</script>";
    }
}
    if(isset($_GET['user_id']))
    {
    $user_id = $_GET['user_id'];
    extract($crud->getID($user_id)); 
}
?>

<div id="Survey-Update">
<form method='post'>
    <table class='table table-bordered'>

        <tr>
            <td>Date Reported</td>
            <td>
                <input name="username" class="form-control" type="text" value="<?php echo $username; ?>">
            </td>

            <td>Remarks</td>
            <td>
                <textarea id="Remarks" type="text" name="password" class="form-control" value="<?php echo $password; ?>">
                </textarea>
            </td>
        </tr>

        <tr>
            <td>Remarks</td>
            <td>
                <textarea id="Remarks" type="text" name="province" class="form-control" value="<?php echo $province; ?>">
                </textarea>
            </td>
        </tr>

        <tr>
            <td colspan="2">
                <button type="submit" class="btn btn-primary" name="btn-update">
                    <span class="edit"></span>Update</button>
                        <a href="insert.php" onClick="self.close()"> &nbsp;  CANCEL</a>
            </td>
        </tr>
    </table>
</form>
</div>

Answer 1

错误表示<form class="form-inline" role="form" id="frmadd" action="<?php echo base_url() ?>index.php/staff_controller/create" method="POST"> <div class="form-group"> <label class="sr-only" for="first_name">First name</label> <input type="text" name="first_name" class="form-control" id="first_name" placeholder="First Name"> </div> <div class="form-group"> <label class="sr-only" for="last_name">Last name</label> <input type="text" name="last_name" class="form-control" id="first_name" placeholder="Last Name"> </div> <div class="form-group"> <label class="sr-only" for="title">Title</label> <?php $attributes = 'class = "form-control" id = "designation"'; echo form_dropdown('designation',$designation, set_value('designation'), $attributes);?> </div> <div class="form-group"> <div class="input-group"> <div class="input-group-addon">@</div> <input class="form-control" name="email" type="email" placeholder="Enter email"> </div> <div class="form-group"> <label class="sr-only" for="address">Address</label> <input type="text" name="address" class="form-control" id="address" placeholder="address"> </div> <div class="form-group"> <label class="sr-only" for="contact_no">Contact</label> <input type="text" class="form-control" name="contact_no" id="contact_no" placeholder="contact number"> </div> <div class="form-group"> <label class="sr-only" for="work_experience">Work Experience</label> <input type="text" class="form-control" name="work_experience" id="work_experience" placeholder="Work Experience"> </div> <div class="form-group"> <label class="sr-only" for="qualifications">Qualifications</label> <input type="text" class="form-control" name="qualifications" id="qualifications" placeholder="Qualifications"> </div> <div class="form-group"> <label class="sr-only" for="nic">NIC</label> <input type="text" class="form-control" name="nic" id="nic" placeholder="NIC"> </div> <div class="form-group"> <input type="submit" class="btn btn-success" id="btn btn-success" value="submit"> </div> </form> </div> <table class="table"> <thead><tr><th>First Name</th><th>Last Name</th><th>Title</th><th>Email</th><th>Address</th><th>Contact</th><th>Work Experience</th><th>Qualifications</th><th>created</th><th>Action</th></tr></thead> <tbody id="fillgrid"> </tbody> <tfoot></tfoot> </table>的数量与bindparams的数量不同。您有4个参数，但只能绑定3个。

你有：

parameters

你应该有类似的东西：

$stmt=$this->db->prepare("UPDATE login SET username=:username,password=:password,province=:province WHERE user_id=:user_id");
$stmt->bindparam(":username",$username);
$stmt->bindparam(":password",$password);
$stmt->bindparam(":province",$province);

您永远不会绑定$stmt=$this->db->prepare("UPDATE login SET username=:username,password=:password,province=:province WHERE user_id=:user_id"); $stmt->bindparam(":username",$username); $stmt->bindparam(":password",$password); $stmt->bindparam(":province",$province); $stmt->bindparam(":user_id",$user_id);参数。

如何在更新时解决此错误？

1 个答案: