Question

我有一个包含字符串的数组，我需要删除包含某个字符串的每个元素。

var arr = ["abc", "123", "dfg", "bbb"];

var string = "b"

删除包含字符串的任何元素后，数组应如下所示：

["123", "dfg"];

Answer 1

与Array.prototype.filter相关：

＆＃13;

var arr = ["abc", "123", "dfg", "bbb"];
var string = "b";

alert(arr.filter(function (i) { return i.indexOf(string) < 0 }))

＆＃13;

Answer 2

您可以简单地遍历数组并收集所有不包含该字符串的项目您可以使用String is [ABCDEFGHIJK#] Position is [4096], string is [ABCDEFGHIJK#], character is [] Position is [2048], string is [ABCDEFGHIJK#], character is [] Position is [1024], string is [ABCDEFGHIJK#], character is [] Position is [512], string is [ABCDEFGHIJK#], character is [] Position is [256], string is [ABCDEFGHIJK#], character is [] Position is [128], string is [ABCDEFGHIJK#], character is [] Position is [64], string is [ABCDEFGHIJK#], character is [] Position is [32], string is [ABCDEFGHIJK#], character is [] Position is [16], string is [ABCDEFGHIJK#], character is [] Position is [8], string is [ABCDEFGHIJK#], character is [I] Found char, len is [8], string is now [IJK#] Position is [4], string is [IJK#], character is [] Position is [2], string is [IJK#], character is [K] Found char, len is [10], string is now [K#] Position is [1], string is [K#], character is [#] Found char, len is [11], string is now [#] 11函数查找一个字符串出现在另一个字符串中。

＆＃13;

indexOf

＆＃13;

请注意，我添加了var arr = ["abc", "123", "dfg", "bbb"]; var string = "b"; var result = []; for (var i = 0; i < arr.length; i++) { if (arr[i].indexOf(string) === -1) { result.push(arr[i]); } } document.body.innerHTML = result;行以显示结果。在您的代码中使用之前不要忘记删除它：）

Answer 3

您也可以使用Array.prototype.splice方法，请检查以下摘录。

＆＃13;

var arr = ["abc", "123", "dfg", "bbb"];
var string = "b";

arr.splice(1,1);
document.getElementById("ans").value = arr[1];

＆＃13;

<input id='ans' type='text'>

＆＃13;

删除数组中包含JavaScript中的字符串的元素

3 个答案: