Question

我正在尝试使用浏览器运行JavaScript文件。

通过这个例子你更容易理解我，我得到了以下代码：（jQuery）

var page = 1;

var data = [];
data.push($('#information').text());
page++;
location = 'www.example.com&page='+page;

我想从以下信息元素中获取文本：

www.example.com&page=1
www.example.com&page=2
www.example.com&page=3

..等等

是否可以使用镀铬扩展？用PHP试了一下，但该网站阻止了我在外面的尝试。

有什么想法吗？

Answer 1

有两种方法可以做到这一点，具体取决于您尝试实现的目标。

如果您想要运行相同的代码段，只需轻松访问即可尝试使用书签。 Here is a video tutorial
您希望在页面上运行JavaScript命令并解析结果，使用Google Chrome的开发者工具，您可以使用F12按钮打开它。

Answer 2

阅读你的问题后我有点困惑，因为这个问题有点不清楚。我想这就是你要找的东西。

class GameScene: SKScene {
    var zombie = SKSpriteNode()
    var spawnPoint1 = CGPointMake(1450, 311)
    var spawnPoint2 = CGPointMake(1968, 406)
    var spawnPoint3 = CGPointMake(1323, 470)
    var mediumZombieMoveSpeed: CGFloat = 2

override func didMoveToView(view: SKView) {
    for var b = 0; b < 5; b++ {
        createZombie()
    }
    }

func createZombie() {
    var randomModel = arc4random_uniform(4)
    var randomPoint = arc4random_uniform(3)


    if randomModel == 0 {
        zombie = SKSpriteNode(texture: zombieTexM1)
        if randomPoint == 0 {
            zombie.position = spawnPoint1
        }
        else if randomPoint == 1 {
            zombie.position = spawnPoint2
        }
        else {
            zombie.position = spawnPoint3
        }

        zombie.physicsBody = SKPhysicsBody(rectangleOfSize: CGSizeMake(32, 32))
        zombie.physicsBody?.restitution = 0
        zombie.physicsBody?.allowsRotation = false
        zombie.name = "zombie"


        world?.addChild(zombie)

    }
    else if randomModel == 1 {
        zombie = SKSpriteNode(texture: zombieTexM2)

        if randomPoint == 0 {
            zombie.position = spawnPoint1
        }
        else if randomPoint == 1 {
            zombie.position = spawnPoint2
        }
        else {
            zombie.position = spawnPoint3
        }
        zombie.physicsBody = SKPhysicsBody(rectangleOfSize: CGSizeMake(32, 32))
        zombie.physicsBody?.restitution = 0
        zombie.physicsBody?.allowsRotation = false
        zombie.name = "zombie"

        world?.addChild(zombie)

    }
    else if randomModel == 2 {
        zombie = SKSpriteNode(texture: zombieTexM3)
        if randomPoint == 0 {
            zombie.position = spawnPoint1
        }
        else if randomPoint == 1 {
            zombie.position = spawnPoint2
        }
        else {
            zombie.position = spawnPoint3
        }
        zombie.physicsBody = SKPhysicsBody(rectangleOfSize: CGSizeMake(32, 32))
        zombie.physicsBody?.restitution = 0
        zombie.physicsBody?.allowsRotation = false
        zombie.name = "zombie"
        world?.addChild(zombie)

    }
    else if randomModel == 3 {
        zombie = SKSpriteNode(texture: zombieTexM4)
        if randomPoint == 0 {
            zombie.position = spawnPoint1
        }
        else if randomPoint == 1 {
            zombie.position = spawnPoint2
        }
        else {
            zombie.position = spawnPoint3
        }



        world?.addChild(zombie)

    }
    else {
        zombie = SKSpriteNode(texture: zombieTexM5)
        if randomPoint == 0 {
            zombie.position = spawnPoint1
        }
        else if randomPoint == 1 {
            zombie.position = spawnPoint2
        }
        else {
            zombie.position = spawnPoint3
        }
        zombie.physicsBody = SKPhysicsBody(rectangleOfSize: CGSizeMake(32, 32))
        zombie.physicsBody?.restitution = 0
        zombie.physicsBody?.allowsRotation = false

        world?.addChild(zombie)
    }
}
    }

Answer 3

我想这就是你想要的。但是如果网站不支持CORS则要小心它不起作用

var page = 1, data = [];
getData();

function getData(){
    if(page>=0){
        $.get('http://websiteurl?page='+page,function(d){
            d = $('<div/>').append(d);
            data.push(d.find('#information').text());
            page++;
            getData();
        }).fail(function(){
            page = -1;
        });
    }
}

如何使用浏览器运行JavaScript文件？

3 个答案: