Question

我试图将表单中的数据插入2个由clientID链接的单独表中，但是我收到错误：

INSERT INTO client_details（clientID，name，email，address，mobile）VALUES（＆＃39;＆＃39;，＆＃39; a＆＃39;，＆＃39; a＆＃39;，＆＃39 ; a＆＃39;，＆＃39; a＆＃39;）; INSERT INTO预订（bookingID，apartmentID，clientID，date_from，date_to，nights，pax，remarks）VALUES（＆＃39;＆＃39;，＆＃39; ; 1＆＃39;，LAST_INSERT_ID（），＆＃39; 2015-08-28＆＃39;，＆＃39; 2015-08-31＆＃39;，＆＃39; 3＆＃39;，＆＃39; 4＆＃39;，＆＃39;额外备注＆＃39;）; 您的SQL语法有错误;查看与您的MySQL服务器版本相对应的手册，以获得正确的语法，以便在预订附近使用{bookingID，apartmentID，clientID，date_from，date_to，night＆＃39;在第1行

<?php
include 'connect.php';

    $apartment = (isset($_POST['apartment']) ? $_POST['apartment'] : null);
    $name = (isset($_POST['name']) ? $_POST['name'] : null);
    $surname = (isset($_POST['surname']) ? $_POST['surname'] : null);
    $email = (isset($_POST['email']) ? $_POST['email'] : null);
    $address = (isset($_POST['address']) ? $_POST['address'] : null);
    $mobile = (isset($_POST['mobile']) ? $_POST['mobile'] : null);
    $pax = (isset($_POST['pax']) ? $_POST['pax'] : null);
    $address = (isset($_POST['address']) ? $_POST['address'] : null);
    $remarks = (isset($_POST['remarks']) ? $_POST['remarks'] : null);
    $day_from = (isset($_POST['day_from']) ? $_POST['day_from'] : null);
    $month_from = (isset($_POST['month_from']) ? $_POST['month_from'] : null);
    $year_from = (isset($_POST['year_from']) ? $_POST['year_from'] : null);
    $booking_from = $year_from."-".$month_from."-".$day_from;
    $day_to = (isset($_POST['day_to']) ? $_POST['day_to'] : null);
    $month_to = (isset($_POST['month_to']) ? $_POST['month_to'] : null);
    $year_to = (isset($_POST['year_to']) ? $_POST['year_to'] : null);
    $booking_to = $year_to."-".$month_to."-".$day_to;
    $no_of_nights = abs(strtotime($booking_to) - strtotime($booking_from));     
    $days = floor($no_of_nights / (60*60*24));

    $sql = "INSERT INTO client_details (clientID, name, email, address, mobile) VALUES ('', '$name $surname', '$email', '$address', '$mobile');";
    $sql.= "INSERT INTO bookings (bookingID, apartmentID, clientID, date_from, date_to, nights, pax, remarks) VALUES ('', '$apartment', LAST_INSERT_ID(), '$booking_from', '$booking_to', '$days', '$pax', '$remarks');";

            if (mysqli_query($conn, $sql)) {
                echo "";
            } else {
                echo "" . $sql . "<br>" .mysqli_error($conn);
  }
  ?>

目标SQL：

BEGIN; INSERT INTO client_detalis（clientID，name，email，address，mobile）价值观（＆＃39;＆＃39;，＆＃39; $ name $ surname＆＃39;，＆＃39; $ email＆＃39;，＆＃39; $ address＆＃39;，＆＃39; $ mobile＆＃ 39）; INSERT INTO预订（bookingID，apartmentID，clientID，date_from，date_to，nights，remarks，pax））价值观（＆＃39;＆＃39;，$ apartment，LAST_INSERT_ID（），＆＃39; $ booking_from＆＃39;，＆＃39; $ booking_to＆＃39;，＆＃39; $ nights＆＃39;，＆＃ 39; $ pax＆＃39;，＆＃39; $ remarks＆＃39;）; COMMIT;

Answer 1

我的回答：

<?php

    $apartment = (isset($_POST['apartment']) ? $_POST['apartment'] : null);
    $name = (isset($_POST['name']) ? $_POST['name'] : null);
    $surname = (isset($_POST['surname']) ? $_POST['surname'] : null);
    $email = (isset($_POST['email']) ? $_POST['email'] : null);
    $address = (isset($_POST['address']) ? $_POST['address'] : null);
    $mobile = (isset($_POST['mobile']) ? $_POST['mobile'] : null);
    $pax = (isset($_POST['pax']) ? $_POST['pax'] : null);
    $address = (isset($_POST['address']) ? $_POST['address'] : null);
    $remarks = (isset($_POST['remarks']) ? $_POST['remarks'] : null);
    $day_from = (isset($_POST['day_from']) ? $_POST['day_from'] : null);
    $month_from = (isset($_POST['month_from']) ? $_POST['month_from'] : null);
    $year_from = (isset($_POST['year_from']) ? $_POST['year_from'] : null);
    $booking_from = $year_from."-".$month_from."-".$day_from;
    $day_to = (isset($_POST['day_to']) ? $_POST['day_to'] : null);
    $month_to = (isset($_POST['month_to']) ? $_POST['month_to'] : null);
    $year_to = (isset($_POST['year_to']) ? $_POST['year_to'] : null);
    $booking_to = $year_to."-".$month_to."-".$day_to;
    $no_of_nights = abs(strtotime($booking_to) - strtotime($booking_from));     
    $days = floor($no_of_nights / (60*60*24));

  include 'connect.php';

 if (!$conn->autocommit(FALSE)) {
    printf("Errormessage: %s\n", $conn->error);
 }

 if (!$conn->query("INSERT INTO client_details (clientID, name, email, address, mobile) VALUES ('', '$name $surname', '$email', '$address', '$mobile')")) {
     printf("Errormessage: %s\n", $conn->error);
 }

 if (!$conn->query("INSERT INTO bookings (bookingID, apartmentID, clientID, date_from, date_to, nights, pax, remarks) VALUES ('', '$apartment', LAST_INSERT_ID(), '$booking_from', '$booking_to', '$days', '$pax', '$remarks')")) {
     printf("Errormessage: %s\n", $conn->error);
 }
// important to insert as code will not work without commit
 if (!$conn->commit()) {
     printf("Errormessage: %s\n", $conn->error);
 }
 $conn->close();


?>

Answer 2

您必须使用mysqli事务方法，如本答案中所述： how-to-start-and-end-transaction-in-mysqli

如何在多个表中插入数据mysqli

2 个答案: