Question

当我输入字段“Age”（这是一个整数）时，除了数字之外的任何数据都会发生错误。我只需要显示验证器的错误消息。

我的模特：

@Entity
@Table(name="user")
public class User {

    @Id
    @GeneratedValue
    private Integer id;

    private String name;

    private Integer age;

    private Boolean isAdmin;

    @GeneratedValue
    private Timestamp createdDate;

验证

public class FormValidator implements Validator {
    private Pattern pattern;
    private Matcher matcher;

    @Override
    public boolean supports(Class<?> aClass) {
        return true;
    }

    @Override
    public void validate(Object o, Errors errors) {
        User user = (User) o;

        ValidationUtils.rejectIfEmptyOrWhitespace(errors,"name", "Mess1", "Mess2");

        if(!(user.getName()!= null && user.getName().isEmpty())) {
            pattern = Pattern.compile("[a-zA-Z]+");
            matcher = pattern.matcher(user.getName());
            if (!matcher.matches()) {
                errors.rejectValue("name", "name contains non char", "enter a valid name");
            }

            if (user.getAge() != null) {
                pattern = Pattern.compile("[0-9]{0,3}");
                matcher = pattern.matcher(user.getAge().toString());
                if (!matcher.matches()) {
                    errors.rejectValue("age", "mess1", "mess2");
                }

                if (user.getAge().toString().length() > 3) {
                    errors.rejectValue("age", "age to big", "not more 3 int");
                }
            }
        }
    }
}

控制器：

@RequestMapping(value="/add", method=RequestMethod.POST)
    public ModelAndView addingUser(@ModelAttribute User user, BindingResult result) {

        FormValidator formValidator = new FormValidator();

        formValidator.validate(user,result);
        if(result.hasErrors()){
            ModelAndView modelAndView = new ModelAndView("add-user-form",result.getModel());

            return modelAndView;
        }

        ModelAndView modelAndView = new ModelAndView("home");
        userService.addUser(user);

        String message = "User was successfully added.";
        modelAndView.addObject("message", message);

        return modelAndView;
    }

据我所知，错误源于页面从已完成的表单中收到旧的错误对象，字段为“age”（其中，数字以外的数据）。

但是如果我分别发送一个新对象和BindingResult形式，则不显示错误。像这样：

if(result.hasErrors()){
            ModelAndView modelAndView = new ModelAndView("add-user-form");
            modelAndView.addObject("user,new User()");
            modelAndView.addObject("errors",result);

            return modelAndView;
        }

如何将BindingResult与坏对象分开发送，或者如何避免这种情况？

错误图片： http://i.stack.imgur.com/YVlt6.png

Answer 1

如果createUser（）方法返回false，请尝试将错误设置为结果对象，如下面的代码。

boolean IsUserCreated = userDAO.createUser(user);
if(isUserCreated == true) {

 } else {
   result.addError(new objectError("emailAddress", "Email ID is already in use")); // here result is BindingResult, emailAddress is the name of the input field in the form.
   modelMap.put("errors", result.getAllErrors());
 }

Spring Validation无法转换属性值异常

1 个答案: