Question

我正在处理需要注册活动的应用。我遇到的问题是每当我离开2个以上的EditTexts时我的应用程序崩溃了：这是我用于注册活动的代码：

import android.app.AlertDialog;
import android.content.Intent;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;


public class Register extends AppCompatActivity implements View.OnClickListener{
EditText etName, etAge, etUsername, etPassword;
Button bRegister;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    etName = (EditText) findViewById(R.id.etName);
    etAge = (EditText) findViewById(R.id.etAge);
    etUsername = (EditText) findViewById(R.id.etUsername);
    etPassword = (EditText) findViewById(R.id.etPassword);
    bRegister = (Button) findViewById(R.id.bRegister);

    bRegister.setOnClickListener(this);
}

@Override
public void onClick(View v) {
    switch (v.getId()) {
        case R.id.bRegister:
            AlertDialog.Builder dialogBuilder = new AlertDialog.Builder(Register.this);
            String name = etName.getText().toString();
            String username = etUsername.getText().toString();
            String password = etPassword.getText().toString();
            int age = Integer.parseInt(etAge.getText().toString());
            if(!(name.trim().length()>0))
            {
                dialogBuilder.setMessage("Please enter your name");
                dialogBuilder.setPositiveButton("Ok", null);
                dialogBuilder.show();
                break;
            }
            if(!(etAge.getText().toString().trim().length()>0)  || age>120)
            {
                dialogBuilder.setMessage("Please enter your age");
                dialogBuilder.setPositiveButton("Ok", null);
                dialogBuilder.show();
                break;
            }
            if(!(username.trim().length()>0))
            {
                dialogBuilder.setMessage("Please enter a username");
                dialogBuilder.setPositiveButton("Ok", null);
                dialogBuilder.show();
                break;
            }
            if(!(password.trim().length()>0))
            {
                dialogBuilder.setMessage("Please enter a password");
                dialogBuilder.setPositiveButton("Ok", null);
                dialogBuilder.show();
                break;
            }
            User user = new User(name, age, username, password);
            registerUser(user);
            break;
    }
}



private void registerUser(User user) {
    ServerRequests serverRequest = new ServerRequests(this);
    serverRequest.storeUserDataInBackground(user, new GetUserCallback() {
        @Override
        public void done(User returnedUser) {
            Intent loginIntent = new Intent(Register.this, LoginScreen.class);
            startActivity(loginIntent);
        }
    });
}

}

Answer 1

也许是因为你的方法中的每个if语句都被调用，这意味着DialogBuilder每次都会尝试显示对话框。

尝试使用：

if(....) {
    ....
}
else if(....){ 
    .....
}
else {
    .....
}

仅供参考：

只会突破封闭的switch，for，while或do-while 构造

android注册活动崩溃

1 个答案: