Select lname, fname, title as "Book Title"
from books join line
on books.bookid = book_author.bookid
join author
on author.authorid = book_author.authorid;
它一直说表或视图不存在,但是当我从书中选择*时;它确实向我展示了这张桌子。
答案 0 :(得分:0)
Select author.lname, author.fname, books.title as "Book Title"
from books join book_author --line
on books.bookid = book_author.bookid
join author
on author.authorid = book_author.authorid;
line
已被评论过。它应该是book_author
。还包括select
子句