Question

我有一个UIwebView，它在网页中有一些链接。我想要一个特定的链接来打开一个警告模式，如图像＃1

此外，如何使用下面的代码制作这样的东西 - （图像＃1）http://screenshot.it.sftcdn.net/blog/it/2014/01/Block-user-03-Tasto-Block-378x568.png在objective-c

- (IBAction)showAlert:(id)sender
{
    UIAlertController *alertController = [UIAlertController alertControllerWithTitle:@"Open In..."
                 message:@"Which app would you like to open?"
          preferredStyle:UIAlertControllerStyleActionSheet];

    UIAlertAction *mapsAction = [UIAlertAction actionWithTitle:@"Maps"
            style:UIAlertActionStyleDefault
          handler:^(UIAlertAction *action) {
              if (![self openURLForString:@"maps://"]) {
                  NSLog(@"Couldn't Open Maps");
              }
          }];
    UIAlertAction *youtubeAction = [UIAlertAction actionWithTitle:@"YouTube"
            style:UIAlertActionStyleDefault
          handler:^(UIAlertAction *action) {
              if (![self openURLForString:@"http://www.youtube.com/watch?v=dQw4w9WgXcQ"]) {
                  NSLog(@"Couldn't Open YouTube");
              }
          }];
    UIAlertAction *messagesAction = [UIAlertAction actionWithTitle:@"Messages"
            style:UIAlertActionStyleDefault
          handler:^(UIAlertAction *action) {
              if (![self openURLForString:@"sms://"]) {
                  NSLog(@"Couldn't Open Messages");
              }
          }];
    UIAlertAction *cancelAction = [UIAlertAction actionWithTitle:@"Cancel"
           style:UIAlertActionStyleCancel
         handler:nil];

    [alertController addAction:mapsAction];
    [alertController addAction:youtubeAction];
    [alertController addAction:messagesAction];
    [alertController addAction:cancelAction];

    [self presentViewController:alertController animated:YES completion:nil];
}

- (BOOL)openURLForString:(NSString *)urlString {
    NSURL *url = [NSURL URLWithString:urlString];
    if ([[UIApplication sharedApplication] canOpenURL:url]) {
        [[UIApplication sharedApplication] openURL:url];
        return YES;
    }
    return NO;
}

“报告不当”是第二个UIwebView中的链接打开，在父网页浏览中打开并且“共享”在Safari中打开。（忽略“复制链接/ URL”）

Answer 1

您需要先为网络视图协议注册视图控制器。

然后在你的视图控制器实现web视图的委托方法确实开始加载并检查被调用的URL并使用if else检查相应地执行任务

这是代表参考：

https://developer.apple.com/library/ios/documentation/UIKit/Reference/UIWebViewDelegate_Protocol/

从我的手机回答。赦免语法。

希望这有帮助。

Objective-C在Safari和Alert Dialog中打开链接

1 个答案: