在图表列表中的scilab中没有显示设置背景图像的选项。我很感激做过这件事的人请指导我这样做。
答案 0 :(得分:1)
新版本的Scilab实际上具有image
个对象的style
uncontrol
。例如,请参见Trity Technologies Sdn Bhd和Chin Luh Tan的this sample。基本上以最简单的形式:
f = figure();
h = uicontrol(f, 'style', 'image', 'string',...
get_absolute_file_path('foo.sce') + 'bar.png')
其中foo.sce
是脚本的名称,bar.png
应替换为要显示的图像的相对地址。
答案 1 :(得分:0)
我不知道“内置”方式,但您可以安装图像处理工具箱。之后,您可以阅读,处理和显示图像。如果你在图像上“绘制”某些东西,它就会成为背景图像:)
global IPD_PATH;
RGB=ReadImage(IPD_PATH+"demos\teaset.png");
//you can also call it with absolute path e.g.: "d:\pics\mypic.jpg"
scf(0);
ShowColorImage(RGB,"Color Image in the background");
//to see these axes set them visible (turned off by default in ShowColorImage)
//c=gca(); c.axes_visible=["on","on","off"];
a=newaxes(); //to use new axes, otherwise your axes go from 0 to the picture size in pixels
a.filled="off"; //to make it transparent
X=1:0.1:10; //some arbitrary data to plot
plot2d(X,sin(X));
//since you dont know the index of the red colour in the current RGB color map, it's easier to do like this:
e=gce(); e.children.foreground=color("red");
plot2d(X,cos(X));
e=gce(); e.children.foreground=color("blue");