我收到以下错误:
"命令不同步;你现在不能运行这个命令"
关于此代码:
$check = $dbc->prepare("SELECT field FROM table WHERE field = ?");
mysqli_stmt_bind_param($check, "s", $value1);
mysqli_stmt_execute($check);
mysqli_stmt_bind_result($check, $info);
mysqli_stmt_fetch($check);
if ( $info == $static_value ) {
$update = $dbc->prepare("UPDATE table SET field = 'valued' WHERE(field1 = ? AND field2 = ?)LIMIT 1");
mysqli_stmt_bind_param($update, "ss", $value1, $value2);
mysqli_stmt_execute($update);
代码看起来正确,我错了吗?
答案 0 :(得分:1)
update
查询看起来非常错误。请尝试以下方法,
您的旧update
,
$update = $dbc->prepare("UPDATE table SET field = 'valued' WHERE(field1 = ? AND field2 = ?)LIMIT 1");
mysqli_stmt_bind_param($update, "ss", $value1, $value2);
mysqli_stmt_execute($update);
您的新$update
,
$update = mysqli_prepare($dbc, "UPDATE `yourTableName` SET `field` = 'valued' WHERE field1 = ? AND field2 = ?");
LIMIT可以与UPDATE一起使用,但仅与行数一起使用。
修改1
您似乎将OO
MySQLi
与procedural
混合在一起,请阅读this页。
修改2
您的代码存在很多问题。
当他们超出$email
的范围时,您试图访问$key
和if
,因此我添加了新变量。
您继续(如上所述)将OO
与procedural
混合。
我在尝试执行$update
时添加了一些调试。
<?php
$email;
$key;
if (isset($_GET['email']) && preg_match('/^([a-zA-Z0-9])+([a-zA-Z0-9\._-])*@([a-zA-Z0-9_-])+([a-zA-Z0-9\._-]+)+$/', $_GET['email'])) {
$email = $_GET['email'];
}
if (isset($_GET['key']) && (strlen($_GET['key']) == 32)) //The Activation key will always be 32 since it is MD5 Hash
{
$key = $_GET['key'];
}
if (isset($email) && isset($key)) {
$check_code = mysqli_prepare($dbc, "SELECT Activation FROM members WHERE Email = ?");
mysqli_stmt_bind_param($check_code, "s", $email);
mysqli_stmt_execute($check_code);
mysqli_stmt_bind_result($check_code, $activation);
mysqli_stmt_fetch($check_code);
if ($activation == $key) {
// Update the database to set the "activation" field to null
$update = mysqli_prepare($dbc, "UPDATE `members` SET `Activation` = 'Activated' WHERE `Email` = ? AND `Activation` = ?");
mysqli_stmt_bind_param($update, "ss", $email, $key);
mysqli_stmt_execute($update);
if (!mysqli_stmt_execute($update) ) {
die("Error: " . mysqli_stmt_error($update));
}
// Print a customized message:
if (mysqli_affected_rows($dbc) == 1) { //if update query was successfull
echo '<div class="success">Your account is now active. You may now <a href="login.php">Log in</a></div>';
} else {
echo '<div class="errormsgbox">Oops !Your account could not be activated. Please recheck the link or contact the system administrator.</div>';
echo '<br/> ' . $dbc->error;
}
mysqli_close($dbc);
} else {
echo "Parameters wrong, wrong link?";
}
} else {
echo '<div class="errormsgbox">Error Occured .</div>';
}
?>
答案 1 :(得分:0)
首先你要混合程序和OOP,其次你没有关闭你的连接,这是另一个错误:)
$check=$dcv->prepare('SELECT field FROM table where field=?');
$check->bind_param('s',$value1);
$check->execute();
$check->bind_result($info);
$check->fetch();
$check->close();
if($info==$static_value){
$update=$dvc->prepare('UPDTATE table SET field='valued' WHERE field1=? AND field2=?');
$update->bind_param('ss',$value1,$value2);
$result=$update->execute();
$update->close();
}