Question

我正在对iOS中的NSString进行加密，编码和解码很好：

NSString *stringtoEncrypt = @"This string is to be encrypted";
NSString *key = @"12345678901234567890123456789012";

// Encode
NSData *plain = [stringtoEncrypt dataUsingEncoding:NSUTF8StringEncoding];
NSData *cipher = [plain AES256EncryptWithKey:key];

NSString *cipherBase64 = [cipher base64EncodedString];
NSLog(@"ciphered base64: %@", cipherBase64);

// Decode
NSData *decipheredData = [cipherBase64 base64DecodedData];
NSString *decoded = [[NSString alloc] initWithData:[decipheredData AES256DecryptWithKey:key] encoding:NSUTF8StringEncoding];
NSLog(@"%@", decoded);

NSData扩展程序：

- (NSData *)AES256EncryptWithKey:(NSString *)key
{
    // 'key' should be 32 bytes for AES256, will be null-padded otherwise
    char keyPtr[kCCKeySizeAES256+1]; // room for terminator (unused)
    bzero(keyPtr, sizeof(keyPtr)); // fill with zeroes (for padding)

    // fetch key data
    [key getCString:keyPtr maxLength:sizeof(keyPtr) encoding:NSUTF8StringEncoding];

    NSUInteger dataLength = [self length];

    //See the doc: For block ciphers, the output size will always be less than or
    //equal to the input size plus the size of one block.
    //That's why we need to add the size of one block here
    size_t bufferSize = dataLength + kCCBlockSizeAES128;
    void *buffer = malloc(bufferSize);

    size_t numBytesEncrypted = 0;
    CCCryptorStatus cryptStatus = CCCrypt(kCCEncrypt, kCCAlgorithmAES128, kCCOptionPKCS7Padding,
                                          keyPtr, kCCKeySizeAES256,
                                          NULL /* initialization vector (optional) */,
                                          [self bytes], dataLength, /* input */
                                          buffer, bufferSize, /* output */
                                          &numBytesEncrypted);
    if (cryptStatus == kCCSuccess) {
        //the returned NSData takes ownership of the buffer and will free it on deallocation
        return [NSData dataWithBytesNoCopy:buffer length:numBytesEncrypted];
    }

    free(buffer); //free the buffer;
    return nil;
}

现在我想将Base64编码的字符串传递给Node.js并让它解码。我正在使用这种方法：

var crypto = require('crypto');

password = '12345678901234567890123456789012';
var cryptoStr = 'q6SIYHKospVNzk5ZsW8S5CURQ8qRPyDhv1TqALXhOVM=';
var iv = "0000000000000000";

var decipher = crypto.createDecipheriv('aes-256-cbc', password, iv);
var dec = decipher.update(cryptoStr,'base64','utf-8');
dec += decipher.final('utf-8'); 

console.log('Decrypted content: ' + dec);

然而结果是：

解密内容：dXYCCDBY ^ WYC要加密

有什么想法会发生什么？

Answer 1

在Objective-C中，你没有定义默认为零填充IV的IV。

的Node.js says

key和iv必须是'二进制'编码的字符串或缓冲区。

IV字符串中的字符0与字节\0不同。你没有传递零填充的IV，而是一个填充了0x30字节的IV。

像这样填写IV：

var iv = new Buffer(16);
iv.fill(0);

Node.js AES解密iOS加密的NSString

1 个答案: