Python局部变量和函数

Question

mood = raw_input("Enter your mood: ").lower()
def setMood(mood):
    mood = "awesome"
    return mood
if mood != "awesome":
    setMood(mood)
    print "Yor mood is now %s!" % mood
else: print "You were awesome anyway!"

为什么这会返回原始输入，而不是函数中覆盖的输入？以及如何解决这个问题？

UPDATE !!!

解决方案：

mood = raw_input("Enter your mood: ").lower()
def setMood(mood):
    mood = "awesome"
    return mood
if mood != "awesome":
    mood = setMood(mood)
    print "Yor mood is now %s!" % mood
else: print "You were awesome anyway!"

Answer 1

mood外setMood是全局的，但其中的select m.* from member m where not exists ( select 1 from group_member gm where gm.member_id = m.member_id and group_id = ? ) 是本地的。有关更多信息，请参阅官方python文档。