按最新创建的日期/时间降序排列数组中的文件名

Question

我正在构建多个图库中所有文件的主数组，我希望图像按创建日期/时间的降序显示。我需要帮助在我的脚本中实现OrderBy。这是正确的方法吗？我真的可以使用一些指导。

// Build Gallery Array
        string[] arctopithecusImages = Directory.GetFiles(arctopithecusGalleryPath, "*.jpg");
        string[] gulonImages = Directory.GetFiles(gulonGalleryPath, "*.jpg");
        string[] scythianWolfImages = Directory.GetFiles(scythianWolfGalleryPath, "*.jpg");
        string[] simivulpaImages = Directory.GetFiles(simivulpaGalleryPath, "*.jpg");
        string[] succorathImages = Directory.GetFiles(succorathGalleryPath, "*.jpg");
        string[] tatusImages = Directory.GetFiles(tatusGalleryPath, "*.jpg");

        // Concatenate Gallery Folders into single Array
        galleryImages = 
            Directory.GetFiles(arctopithecusGalleryPath, "*.jpg")
                .Concat(gulonImages)
                .Concat(scythianWolfImages)
                .Concat(simivulpaImages)
                .Concat(succorathImages)
                .Concat(tatusImages).OrderBy(f => f.All)
                .ToArray();

Answer 1

我认为你应该使用DirectoryInfo课程。它将为您提供的不仅仅是文件名。然后您就可以按文件属性订购

DirectoryInfo diArctopithecusDirectory = new DirectoryInfo(arctopithecusGalleryPath);
FileInfo[] arctopithecusImages = diArctopithecusDirectory.GetFiles("*.jpg");

DirectoryInfo diGulonImagesDirectory = new DirectoryInfo(gulonGalleryPath);
FileInfo[] arctopithecusImages = diGulonImagesDirectory.GetFiles("*.jpg");

DirectoryInfo diScythianWolfDirectory = new DirectoryInfo(scythianWolfGalleryPath);
FileInfo[] scythianWolfImages = diScythianWolfDirectory.GetFiles("*.jpg");

FileInfo[]  result = arctopithecusImages.Union(arctopithecusImages)
                    .Union(scythianWolfImages)
                    .OrderByDescending(p => p.CreationTime)
                    .ToArray();

如果您只需要文件名，则可以执行类似

的操作

string[] result = arctopithecusImages.Union(arctopithecusImages)
                                    .Union(scythianWolfImages)
                                    .OrderByDescending(p => p.CreationTime)
                                    .Select(x => x.Name)
                                    .ToArray();