Question

我正在尝试使用cakephp 1.3中的cakephp virtualFields。我的sql查询如下，但我需要day_index（我的虚拟字段）为＆＃39; DAYOFWEEK（start_date）＆＃39;。

我需要重写一个查询

$data = $this->Calendar->query("SELECT *, DAYOFWEEK(start_date) as day_index, TIME(start_time) as time 
    FROM calendars WHERE calendar_category_id =$cal ORDER BY day_index, time");

采用以下格式：

$sqlConditions = array("Calendar.calendar_category_id"=>$cal);
$sqlOrderBy = array("Calendar.day_index", "Calendar.time asc");
$sqlParams = array('conditions'=>$sqlConditions,'order'=>$sqlOrderBy);
$data = $this->Calendar->find('all',$sqlParams);
$this->set('data',$data);

所以我不确定如何/在哪里放置或声明虚拟字段。

$fields = $this->Calendar->virtualFields['day_index'].'AS 'DAYOFWEEK(start_date)';

Answer 1

找到两种方法来做到这一点，不确定一个是否优于另一个。 控制器仅编辑方法

$sqlFields = array("DAYOFWEEK(Calendar.start_date) as day_index",
    "TIME(Calendar.start_time) as time",
    "Calendar.start_date",
    "Calendar.calendar_category_id",
    "Calendar.start_time");
    $sqlConditions = array("Calendar.calendar_category_id"=>$cal);
    $sqlOrderBy = array("Calendar.day_index, Calendar.time asc"); 
    $sqlParams = array('fields'=>$sqlFields,'conditions'=>$sqlConditions,'order'=>$sqlOrderBy);
    $data = $this->Calendar->find('all',$sqlParams);
    return $data;
    exit();

基于此方法编辑控制器的模型方法 型号＆gt;

var $virtualFields = array(  
   'day_index' => "DAYOFWEEK(Calendar.start_date)",
   'time' => "TIME(Calendar.start_time)"
 );  
 var $displayIndex = 'day_index'; 
 var $displayTime = 'time';

控制器＆gt;

$sqlConditions = array("Calendar.calendar_category_id"=>$cal);
    $sqlOrderBy = array("Calendar.day_index, Calendar.time asc"); 
    $sqlParams = array('conditions'=>$sqlConditions,'order'=>$sqlOrderBy);
    $data = $this->Calendar->find('all',$sqlParams);
    return $data;
    exit();

cakephp SQL查询中的虚拟字段

1 个答案: