获取scala中闭包的字符串表示形式

Question

scala> val f = (x:Int) => x+1
f: Int => Int = <function1>

scala> println(f)
<function1>

是否可以在程序（而不是控制台）中打印f: Int => Int = <function1>字符串？我主要需要Int => Int部分进行测试。

Answer 1

也许：类型就是你想要的

scala> val f = (x:Int) => x+1
f: Int => Int = <function1>

scala> :type f
Int => Int

既然你想在程序中获得它，那么TypeTag可能是一个选择

scala> :paste
// Entering paste mode (ctrl-D to finish)

import scala.reflect.runtime.{ universe => ru }
import scala.reflect.runtime.universe.{ TypeTag, typeTag }
def getTypeTag[T: TypeTag](o: T) = typeTag[T].tpe

// Exiting paste mode, now interpreting.

scala> val f = (x:Int) => x+1
f: Int => Int = <function1>

scala> getTypeTag(f)
res0: reflect.runtime.universe.Type = Int => Int

scala> getTypeTag(f).toString
res1: String = Int => Int

Answer 2

您可以通过

获得

f.getClass