Question

我在YouTube api中的onError事件遇到了一些问题。下面是一个带有假videoId的脚本，用于创建一个调用函数onPlayerError的错误。不幸的是我无法理解为什么错误函数被调用两次。我认为这可能与函数内部的回调响应（可能是？）有关，但是当videoId正确时，onReady或onStateChange都不会被调用两次。谁能看到任何明显的问题？提前谢谢。

BTW：是的，我确实需要回调和回调中的响应。这是我完整脚本的缩短版本。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en">

<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

<!-- jQuery -->
<script type="text/javascript" src="http://code.jquery.com/jquery-1.11.0.min.js"></script>

<!-- jQuery / javascript for page -->
<script type='text/javascript'>
//<![CDATA[ 

//create deferred object
var YTdeferred = $.Deferred();

//attach a function to onYouTubeIframeAPIReady
window.onYouTubeIframeAPIReady = function() {
    //resolve when youtube callback is called passing YT as a parameter
    YTdeferred.resolve(window.YT);
    console.log('Resolved');
};

//embed youtube api script
var tag = document.createElement('script');
tag.src = "https://www.youtube.com/iframe_api";
var firstScriptTag = document.getElementsByTagName('script')[0];
firstScriptTag.parentNode.insertBefore(tag, firstScriptTag);

//create player variable
var player;

//create YouTube player
function createyoutubeplayer(nextPageToken)
{
    //whenever youtube callback was called = deferred resolved
    //your custom function will be executed with YT as an argument
    YTdeferred.done(function(YT) {
    console.log("create player");
        //create new player
        player = new YT.Player('player', {
            height: '390',
            width: '640',
            videoId: 'fff',
            playerVars: {
                'rel': 0,
                'autohide': 1,
                'controls': 1,
                'showinfo': 0,
                'iv_load_policy': 3,
                'fs': 0,
                'modestbranding': 0,
                'playsinline': 1,
                'enablejsapi': 1
            },
            events: {
                'onError': onPlayerError,
                'onReady': onPlayerReady,
                'onStateChange': onPlayerStateChange
            }
        });
    });
}

//when YouTube player is ready
function onPlayerReady(event)
{
    //play video
    event.target.playVideo();

    //unmute sound and set the volume
    event.target.unMute();
    event.target.setVolume(80);
}

//when YouTube video ends
function onPlayerStateChange(event)
{       
    //if finished playing     
    if(event.data === 0)
    {     
        //call next video function       
        //nextvideo(event);
    }
}

function onPlayerError(event)
{
    //call next video function  
    //nextvideo(event);
    console.log('Error: ' + event.data);
    player.stopVideo();
}


createyoutubeplayer();

//]]>  
</script>

</head>

<body>

    <!-- video player -->
    <div id="player"></div>

</body>
</html>

Answer 1

我认为你错过了听众。

player.addEventListener(event:String, listener:String):Void

https://developers.google.com/youtube/iframe_api_reference#addEventListener

YouTube iframe api - 为什么onError事件被调用两次？

1 个答案: