Question

我有导航控制器和根视图。然后在那个根视图中，我按下了一个视图，我必须单击才能观看内容，如果没有登录，它将打开一个带有以下代码的模态视图控制器。

        var vc = self.storyboard?.instantiateViewControllerWithIdentifier("LoginViewController") as! LoginViewController
        self.tabBarController!.presentViewController(vc, animated: true, completion: nil)

在viewdidload（）中我有一个nsnotification，以便在用户从登录模式登录时收到通知

 NSNotificationCenter.defaultCenter().addObserver(self, selector: ("didDismissSecondViewController:"), name: "SecondViewControllerDismissed", object: nil)

在登录控制器完成所有工作后，我编写了以下代码

 self.dismissViewControllerAnimated(true, completion: {NSNotificationCenter.defaultCenter().postNotificationName("SecondViewControllerDismissed", object: nil, userInfo: nil)});

所以在我的第一个视图控制器中，我编写了以下代码

func didDismissSecondViewController(sender: AnyObject)
{
    NSLog("Called ns notifications")
    dispatch_async(dispatch_get_main_queue(),{

        let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
        if Reachability.isConnectedToNetwork() == true {
let storyboard : UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
        let vc : VideoPlayViewController = storyboard.instantiateViewControllerWithIdentifier("video") as! VideoPlayViewController
        vc.movieUrl = self.movieURL
        NSLog("URL:- \(self.movieURL)")
        let navigationController = UINavigationController(rootViewController: vc)

        self.presentViewController(navigationController, animated: true, completion: nil)

        }
        else
        {

         var alert = UIAlertView(title: "No Internet connection", message: "Please ensure you are connected to the Internet. Connect to internet and and choose any sorting option to reload.", delegate: self,  cancelButtonTitle: "Cancel")
                alert.addButtonWithTitle("Ok")
                alert.show()


        }


    })

}

但是，当它在解除登录控制器后尝试显示视图控制器时，它会显示＆＃34;不鼓励在分离的视图控制器上显示视图控制器＆＃34;错误，它崩溃了。

Answer 1

感谢上帝，我找到了答案!!!

     foreach (var f in files)
     {
        using (Bitmap b = (Bitmap)Image.FromFile(f))
        {
           //Do some work
        }
     }

＆＃34;不鼓励在分离的视图控制器上呈现视图控制器＆＃34;提出模态时的消息

1 个答案: