Question

我正在尝试更新数据库中的某些值，我获取要更新的值的主表具有以下结构：

http://api.football-data.org/alpha/soccerseasons/403/leagueTable 所以在更新查询中我执行以下语句：

UPDATE leaguetable SET matchDay = ?, position = ?, teamName = ?, 
playedGames = ?, points = ?, goals = ?, goalsAgainst = ?, 
goalDifference = ?, self = ?, soccerSeason = ?, team = ? WHERE
self LIKE 'http://api.football-data.org/alpha/soccerseasons/403/leagueTable'"

此查询是正确的，但是当我在PhpMyAdmin的控制台中尝试它时，它会返回0 rows，因为值self具有以下结构：

http://api.football-data.org/alpha/soccerseasons/403/leagueTable/?matchday=2

我在like属性中做错了什么？

注意：我在名为http://api.football-data.org/alpha/soccerseasons/403/leagueTable的变量中传递值$x，在帖子中链接只是一个显示链接布局的示例。

Answer 1

尝试使用％（通配符）后：

UPDATE leaguetable SET matchDay = ?, position = ?, teamName = ?, 
        playedGames = ?, points = ?, goals = ?, goalsAgainst = ?, 
        goalDifference = ?, self = ?, soccerSeason = ?, team = ?    WHERE self     LIKE 'http://api.football-data.org/alpha/soccerseasons/403/leagueTable%'

Answer 2

您必须使用通配符来获取输出

UPDATE leaguetable SET matchDay = ?, position = ?, teamName = ?, 
playedGames = ?, points = ?, goals = ?, goalsAgainst = ?, 
goalDifference = ?, self = ?, soccerSeason = ?, team = ?    WHERE self LIKE 'http://api.football-data.org/alpha/soccerseasons/403/leagueTable%'"

Answer 3

您需要包含通配符%才能正常工作。

在此处详细了解MSDN LIKE

特别是关于通配符%

'http://api.football-data.org/alpha/soccerseasons/403/leagueTable%'发现所有网址都以给定的开头，包括所需的/?matchday=2。

在您的代码中：

UPDATE leaguetable 
SET matchDay = ?, position = ?, teamName = ?, playedGames = ?, points = ?, goals = ?, goalsAgainst = ?, goalDifference = ?, self = ?, soccerSeason = ?, team = ?    
WHERE self LIKE 'http://api.football-data.org/alpha/soccerseasons/403/leagueTable%'

LIKE运算符无法正常工作

3 个答案: