如何使用C＃从端口9999打开应用程序

Question

我想使用c＃代码打开应用程序。应用程序需要在端口号9999处打开。我不知道该怎么做。

谢谢。

Answer 1

你可以试试这个

  private void SendToServer(IPAddress IP, int Port) {
        try {
            TcpClient tcpclnt = new TcpClient();
            tcpclnt.Connect(IP, Port);
            //your code here
            }

  

UPDATE   对于服务器，您将使用此

public static void Main() {
            TcpListener serverSocket = new TcpListener(9999);
            TcpClient clientSocket = default(TcpClient);
            int counter = 0;
            serverSocket.Start();
            Console.WriteLine(" >> " + "Server Started");
            counter = 0;
            while (true) {
                counter += 1;
                clientSocket = serverSocket.AcceptTcpClient();
                Console.WriteLine(" >> " + "Client No:" + Convert.ToString(counter) + " started!");
                handleClient client = new handleClient();
                client.startClient(clientSocket, Convert.ToString(counter));
            }

            clientSocket.Close();
            serverSocket.Stop();
            Console.WriteLine(" >> " + "exit");
            Console.ReadLine();
        }
    }

    public class handleClient {
//yourcodehere
}

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