Question

$title=Canon PowerShot SX130IS 12.1 MP Digital Camera with 12x Wide 
Angle Optical Image Stabilized Zoom with 3.0-Inch LCDCanon PowerShot 
SX130IS 12.1 MP Digital Camera with 12x Wide Angle Optical Image 
Stabilized Zoom with 3.0-Inch LCD

希望输出为：

$title = Canon PowerShot SX130IS

Without在php中使用strpos，因为有一组数据，其中string的位置不同.Hence想要删除一个模式之后的数据。 after 12.1 MP我想删除所有内容。所以任何人都可以告诉我我能为它写出什么样的模式。 e.g. 12.1 MP camera(red),14.1 MP camera(blue) many characters written after that to be removed of from it 请有人给我所需的模式!!

Answer 1

如果您想处理不同的百万像素，可以使用以下内容：

preg_replace('/\s\d+\.?\d*\sMP.*/', "", "Canon PowerShot SX130IS 15.4 MP Digital Camera blabla");

另一个变化也是“... SX130IS / 15.4 MP ......”和“...... 15.4MP ......”将是：

preg_replace('/(\s|\/)\d+\.?\d*\s?MP.*/', "", "Canon PowerShot SX130IS 15.4 MP Digital Camera blabla");

Answer 2

这将根据MP位置返回字符串值。

    function foo($title) {        
        $title_array = explode(' ',$title);
        foreach ($title_array as $key => $value) {
            if($value === "MP"){
                $title = implode(' ',array_slice($title_array, 0, $key));
                return $title;
            }
        }
    }

    foo($title);

Answer 3

list($result) = explode("MP", $title, 2);
$result[0] = 'Canon PowerShot SX130IS 12.1 MP'

使用php删除字符串中某些字符后的数据

3 个答案: