Question

我理解如何显示列中最常出现的5个值：

select top 5 col1, count(col1)
from table1
group by col1
order by count(col1) desc;

但是，如何创建一个查询，显示同一列中不属于上述查询结果的所有其他值？

我尝试了以下子查询：

select col1
from table1
where col1 not in 
    (select top 5 col1, count(col1)
     from table1
     group by col1
     order by count(col1) desc);

但是查询失败，我收到以下错误消息：

当选择列表中只能指定一个表达式时子查询不是用EXISTS引入的。

Answer 1

对于Sql Server 2012+，您可以使用offset：

select col1, count(col1)
from table1
group by col1
order by count(col1) desc
offset 5 rows

您可能希望在此处为您的订购添加决胜局，以使其具有确定性：

select col1, count(col1)
from table1
group by col1
order by count(col1) desc, col1
offset 5 rows

Answer 2

问题是您无法在subquery内选择多个列。

(select top 5 col1, count(col1)..

您可以从子查询中删除count(col1)，但NOT IN col1中的subquery NULL值

时，

with cte as
(
select top 5 col1
from table1
group by col1
order by count(col1) desc
)
select * from table1 A
where not exists (select 1 from cte B where a.Col=b.col)

子句可能会失败

尝试像这样改变

normalize-space(.//div[@class="jt_jobs_title"]/text())
            HERE^

Answer 3

使用OFFSET

select col1, count(col1)
from table1
group by col1
order by count(col1) desc
OFFSET 5 ROWS -- skip 5 rows, must use with order by

SQL：如何列出不是同一列的5个最高值的列的值？

3 个答案: