我希望此函数在数组中显示最高值和索引。如果索引最高，它将检索sql中的所有值。但是当我运行这个程序时，它会显示很多值...如何解决？
private void pick_highest_value_here_and_display(ArrayList<Double> value) throws Exception {
// TODO Auto-generated method stub
double aa[]=value.stream().mapToDouble(v -> v.doubleValue()).toArray();
double highest=aa[0];
System.out.println(highest); // display value in aa[0]
for(int i=1;i<aa.length;i++)
{
if(aa[i]>highest)
{
highest=aa[i];
System.out.println(highest); //print the highest value only
System.out.println(i);
String sql ="Select * from placeseen where ID =?";
DatabaseConnection db = new DatabaseConnection();
Connection conn =db.getConnection();
PreparedStatement ps = conn.prepareStatement(sql);
ps.setDouble(1, i+1);
ResultSet rs = ps.executeQuery();
if (rs.next())
{
String aaa=rs.getString("place1");
String bbb=rs.getString("place2");
String cc=rs.getString("place3");
String dd=rs.getString("place4");
String ee=rs.getString("place5");
String ff=rs.getString("place6");
String gg=rs.getString("place7");
String hh=rs.getString("place8");
String iii=rs.getString("place9");
String jj=rs.getString("place10");
String kk=rs.getString("place11");
String ll=rs.getString("place12");
String mm=rs.getString("place13");
String nn=rs.getString("place14");
String oo=rs.getString("place15");
String pp=rs.getString("budget");
Tourism to =new Tourism();
to.setPlace1(aaa);
to.setPlace2(bbb);
to.setPlace3(cc);
to.setPlace4(dd);
to.setPlace5(ee);
to.setPlace6(ff);
to.setPlace7(gg);
to.setPlace8(hh);
to.setPlace9(iii);
to.setPlace10(jj);
to.setPlace11(kk);
to.setPlace12(ll);
to.setPlace13(mm);
to.setPlace14(nn);
to.setPlace15(oo);
to.setBudget(pp);
DispDay dc=new DispDay();
dc.setVisible(true);
}
ps.close();
rs.close();
conn.close();
}
else if(highest==aa[0])
{
String sql ="Select * from placeseen where ID =1";
DatabaseConnection db = new DatabaseConnection();
Connection conn =db.getConnection();
PreparedStatement ps = conn.prepareStatement(sql);
ResultSet rs = ps.executeQuery();
if (rs.next())
{
String aaa=rs.getString("place1");
String bbb=rs.getString("place2");
String cc=rs.getString("place3");
String dd=rs.getString("place4");
String ee=rs.getString("place5");
String ff=rs.getString("place6");
String gg=rs.getString("place7");
String hh=rs.getString("place8");
String iii=rs.getString("place9");
String jj=rs.getString("place10");
String kk=rs.getString("place11");
String ll=rs.getString("place12");
String mm=rs.getString("place13");
String nn=rs.getString("place14");
String oo=rs.getString("place15");
String pp=rs.getString("budget");
Tourism to =new Tourism();
to.setPlace1(aaa);
to.setPlace2(bbb);
to.setPlace3(cc);
to.setPlace4(dd);
to.setPlace5(ee);
to.setPlace6(ff);
to.setPlace7(gg);
to.setPlace8(hh);
to.setPlace9(iii);
to.setPlace10(jj);
to.setPlace11(kk);
to.setPlace12(ll);
to.setPlace13(mm);
to.setPlace14(nn);
to.setPlace15(oo);
to.setBudget(pp);
DispDay dc=new DispDay();
dc.setVisible(true);
}
ps.close();
rs.close();
conn.close();
}
}
答案 0 :(得分：2)
MAX 请更改您的方法，并使用SQL MAX function。像，
String sql = "SELECT * FROM placeseen WHERE budget = ("
+ "SELECT MAX(budget) FROM placeseen)";
然后你可以使用像
这样的东西int id = rs.getInt("id");
float budget = rs.getFloat("budget");
我建议限制列（如果你只想要两个），如
String sql = "SELECT id, budget FROM placeseen WHERE budget = ("
+ "SELECT MAX(budget) FROM placeseen)";
答案 1 :(得分：0)
为什么不使用'set up the output workbook
Set OutBook = ThisWorkbook 'Worksheets.Add
Set OutSheet = OutBook.Sheets.Add
OutSheet.Name = "Repair Summary"
Set OutSheet = OutBook.Sheets(1)
'loop through all files
For FileIdx = 1 To TargetFiles.SelectedItems.Count
'open the file and assign the workbook & worksheet
Set DataBook = Workbooks.Open(TargetFiles.SelectedItems(FileIdx))
Set DataSheet = DataBook.Sheets("Repair Summary by Location")
'identify row/column boundaries
LastDataRow = DataSheet.Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row
LastDataCol = DataSheet.Cells.Find("*", SearchOrder:=xlByColumns, SearchDirection:=xlPrevious).Column
'if this is the first go-round, include the header
If FileIdx = 1 Then
Set DataRng = Range(DataSheet.Cells(HeaderRow, 1), DataSheet.Cells(LastDataRow, LastDataCol))
Set OutRng = Range(OutSheet.Cells(HeaderRow, 1), OutSheet.Cells(LastDataRow, LastDataCol))
'if this is NOT the first go-round, then skip the header
Else
Set DataRng = Range(DataSheet.Cells(HeaderRow, 1), DataSheet.Cells(LastDataRow, LastDataCol))
Set OutRng = Range(OutSheet.Cells(LastOutRow + 2, 1), OutSheet.Cells(LastOutRow + 2 + LastDataRow, LastDataCol))
End If
'copy the data to the outbook
DataRng.Copy OutRng
'close the data book without saving
DataBook.Close False
'update the last outbook row
LastOutRow = OutSheet.Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row
Next FileIdx
？
将for (int i = 0; i < array.lenght; i++)存储在变量中，并将该索引中的实际array[i]存储在另一个变量中。然后，当你更多地循环它：int时，将新索引号和新的最大整数存储在它们的相应变量中。