如何在弹出框中加载laravel视图页面

Question

我想在我的laravel 5 app的弹出框中加载更新/删除视图。目前我已经在一个单独的窗口中打开了一个链接。请指教我

这是我的链接
list.blade.php

   <td><a href="{{url('user-edit',$user->id)}}">Update</a></td>

这是我要加载的表单

update.blade.php

<form class="form-horizontal" role="form" method="POST" action="{{ action('Admin\UserController@update', ['id' => $user->id]) }}">

        <input type="hidden" name="_token" value="{{ csrf_token() }}">

        <div class="form-group">
            <label class="col-md-4 control-label">Full Name</label>
            <div class="col-md-6">
                <input  type="text" class="form-control" name="full_name" value="{{ $user->full_name }}">
            </div>
        </div>

        <div class="form-group">
            <label class="col-md-4 control-label">Username</label>
            <div class="col-md-6">
                <input  type="text" class="form-control" name="username" value="{{ $user->username }}">
            </div>
        </div>

        <div class="form-group">
            <label class="col-md-4 control-label">Password</label>
            <div class="col-md-6">
                <input  type="text" class="form-control" name="password" value="{{ $user->password }}">
            </div>
        </div>



        <div class="form-group">
            <div class="col-md-6 col-md-offset-4">
                <button type="submit" class="btn btn-primary">
                    Register
                </button>
            </div>
        </div>

    </form>
    <div class="col-md-6 text-right">

        {!! Form::open([
        'method' => 'DELETE',
        'route' => ['destroy', $user->id]
        ]) !!}
        <button type="submit" class="btn btn-danger">
            Delete
        </button>
        {!! Form::close() !!}
    </div>