我有一个门户,其中管理员创建转销商。每个经销商都可以拥有自己的用户。因此,在用户表中,它们使用转销商进行映射。所以现在我想只显示那些映射到他的 ID 的用户。那么如何只显示那些映射到他的帐户的用户。我的保存功能提取所有用户,但我想获取该经销商的用户,该用户已登录而不是获取所有记录。
以下是我的代码:
控制器:
public function index ()
{
// Fetch all users
$this->data['users'] = $this->reseller_m->get();
// Load view
$this->data['subview'] = 'reseller/user/index';
$this->load->view('reseller/_layout_main', $this->data);
}
型号:
public function login ()
{
$user = $this->get_by(array(
'email' => $this->input->post('email'),
'password' => $this->hash($this->input->post('password')),
), TRUE);
if (count($user)) {
// Log in user
$data = array(
'name' => $user->name,
'email' => $user->email,
'id' => $user->id,
'loggedin' => TRUE,
);
$this->session->set_userdata($data);
}
}
public function logout ()
{
$this->session->sess_destroy();
$this->session->unset_userdata('logged_in','id','name','email');
}
public function loggedin ()
{
return (bool) $this->session->userdata('loggedin');
}
存在保存功能的基本模型。
public function get($id = NULL, $single = FALSE){
if ($id != NULL) {
$filter = $this->_primary_filter;
$id = $filter($id);
$this->db->where($this->_primary_key, $id);
$method = 'row';
}
elseif($single == TRUE) {
$method = 'row';
}
else {
$method = 'result';
}
return $this->db->get($this->_table_name)->$method();
}
public function get_by($where, $single = FALSE){
$this->db->where($where);
return $this->get(NULL, $single);
}
public function save($data, $id = NULL){
// Set timestamps
if ($this->_timestamps == TRUE) {
$now = date('Y-m-d H:i:s');
$id || $data['created'] = $now;
$data['modified'] = $now;
}
// Insert
if ($id === NULL) {
!isset($data[$this->_primary_key]) || $data[$this->_primary_key] = NULL;
$this->db->set($data);
$this->db->insert($this->_table_name);
$id = $this->db->insert_id();
}
// Update
else {
$filter = $this->_primary_filter;
$id = $filter($id);
$this->db->set($data);
$this->db->where($this->_primary_key, $id);
$this->db->update($this->_table_name);
}
return $id;
}
查看档案:
<?php if(count($users)): foreach($users as $user): ?>
<tr class="info">
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->sip_username); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->sip_password); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->key); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->name); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->status); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->email); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->phone); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->balance); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->created); ?></td>
<td><?php echo anchor('admin/user/edit/' . $user->id, $user->modified); ?></td>
<td><?php echo btn_edit('admin/user/edit/' . $user->id); ?></td>
<td><?php echo btn_delete('admin/user/delete/' . $user->id); ?></td>
</tr>
<?php endforeach; ?>
<?php else: ?>
<tr>
<td colspan="3">We could not find any users.</td>
</tr>
<?php endif; ?>
答案 0 :(得分:1)
首先,当用户login.check usertype并在session中包含usertype。 或
)
您的模型string country = "COTE D’IVOIRE"
bool isValid = Regex.IsMatch(country.Trim(), @"^[a-zA-Z\-'()/.,\s]+$");
代码
public function index ()
{
// Fetch all users
$session_data = $this->session->userdata('logged_in');
$id = $session_data['id'];
$data['users'] = $this->reseller_m->get($id)
// Load view
$data['subview'] = 'reseller/user/index';
$this->load->view('reseller/_layout_main', $data);
}
在您的视图文件中
reseller_m.php