Centos 7 phpmyadmin 403 Forbidden

时间:2015-08-06 10:32:20

标签: apache phpmyadmin centos7 selinux

当我尝试在Centos 7上运行localhost / phpmyadmin时出现权限错误:

Forbidden

You don't have permission to access /phpmyadmin on this server.

我已经搜索并做了所有事情。

我的/etc/httpd/conf.d/phpmyadmin.conf文件是:

<Directory "/usr/share/phpmyadmin">
   Order Deny,Allow
#   Deny from all
   Allow from 127.0.0.1
</Directory>

Alias /phpmyadmin /usr/share/phpmyadmin
Alias /phpMyAdmin /usr/share/phpmyadmin
Alias /mysqladmin /usr/share/phpmyadmin

我也用过:

Allow from all

我的/usr/share/phpmyadmin/config.inc.php是:

<?php
/* vim: set expandtab sw=4 ts=4 sts=4: */
/**
 * phpMyAdmin sample configuration, you can use it as base for
 * manual configuration. For easier setup you can use scripts/setup.php
 *
 * All directives are explained in Documentation.html and on phpMyAdmin
 * wiki <http://wiki.phpmyadmin.net>.
 *
 * @version $Id$
 */

/*
 * This is needed for cookie based authentication to encrypt password in
 * cookie
 */
$cfg['blowfish_secret'] = ''; /* YOU MUST FILL IN THIS FOR COOKIE AUTH! */

/*
 * Servers configuration
 */
$i = 0;

/*
 * First server
 */
$i++;
/* Authentication type */
$cfg['Servers'][$i]['auth_type'] = 'http';
/* Server parameters */
$cfg['Servers'][$i]['host'] = 'localhost';
$cfg['Servers'][$i]['connect_type'] = 'tcp';
$cfg['Servers'][$i]['compress'] = false;
/* Select mysqli if your server has it */
$cfg['Servers'][$i]['extension'] = 'mysql';
/* User for advanced features */
// $cfg['Servers'][$i]['controluser'] = 'pma';
// $cfg['Servers'][$i]['controlpass'] = 'pmapass';
/* Advanced phpMyAdmin features */
// $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin';
// $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark';
// $cfg['Servers'][$i]['relation'] = 'pma_relation';
// $cfg['Servers'][$i]['table_info'] = 'pma_table_info';
// $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords';
// $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages';
// $cfg['Servers'][$i]['column_info'] = 'pma_column_info';
// $cfg['Servers'][$i]['history'] = 'pma_history';
// $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords';

/*
 * End of servers configuration
 */

/*
 * Directories for saving/loading files from server
 */
$cfg['UploadDir'] = '';
$cfg['SaveDir'] = '';

?>

我还更改了/ var / www /&#34; 755&#34;和禁用的SElinux。

我尝试的另一件事是在开头使用它:

<Directory /usr/share/phpMyAdmin/>
   AddDefaultCharset UTF-8

   <IfModule mod_authz_core.c>
     # Apache 2.4
     <RequireAny>
       #Require ip 127.0.0.1
       #Require ip ::1
       Require all granted
     </RequireAny>
   </IfModule>
   <IfModule !mod_authz_core.c>
     # Apache 2.2
     Order Deny,Allow
     Deny from All
     Allow from 127.0.0.1
     Allow from ::1
   </IfModule>
</Directory>

我做的每一次改变我都重启了apache&#34; sudo systemctl restart httpd.service&#34; 我尝试了一切,但没有运气。我仍然得到错误。任何想法? 谢谢!

3 个答案:

答案 0 :(得分:2)

试试这样:

我只需用我的IP和Viola替换127.0.0.1 IP!
所以我想只需更换“Require ip 127.0.0.1”&amp; “需要ip :: 1”和“需要全部授权”就可以了。

答案 1 :(得分:1)

不要用yum安装phpmyadmin。它有很多错误要打开,尝试从phpmyadmin官方网站下载并将其解压缩到你的/ var / www / html目录并将文件夹重命名为phpmyadmin并重新启动你的httpd服务。现在检查一点也不用担心。

答案 2 :(得分:0)

<form action="" method="POST">
Name:    <input type="text" name="input[0][name]" value="">
Address:  <input type="text" name="input[0][address]" value="">
Mobile: <input type="text" name="input[0][mobile]" value="">
Product <input type="text" name="product[0][product]" value="">
Product1 <input type="text" name="product[1][product]" value="">
Product2 <input type="text" name="product[2][product]" value="">

<input type="submit" name="submit" id="submit" value="Submit">


<?php

$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

if(isset($_POST['submit'])) {
    $input = $_POST['input'];
    $product = $_POST['product'];   
    if(!empty($input) && !empty($product)){
    for($i=0; $i<count($product); $i++){        
        $fname = $input[0]['name'];
        $address = $input[0]['address'];
        $mobile = $input[0]['mobile'];
        $product = $product[$i]['product'];
        $sql = "INSERT INTO table_name (id, name, address, mobile, product) VALUES('', '$fname' , '$address', '$mobile' , '$product')";

        if (mysqli_query($conn, $sql)) {
           echo "New record created successfully";
         } else {
           echo "Error: " . $sql . "<br>" . mysqli_error($conn);
       }

       mysqli_close($conn);

    }
}
}    
?>

您提到的上述代码为我工作